li haitao
Followers: 0 Following: 0
Statistics
RANK
5,744
of 289,890
REPUTATION
8
CONTRIBUTIONS
0 Questions
1 Answer
ANSWER ACCEPTANCE
0.00%
VOTES RECEIVED
2
RANK
of 19,604
REPUTATION
N/A
AVERAGE RATING
0.00
CONTRIBUTIONS
0 Files
DOWNLOADS
0
ALL TIME DOWNLOADS
0
CONTRIBUTIONS
0 Posts
CONTRIBUTIONS
0 Public Channels
AVERAGE RATING
CONTRIBUTIONS
0 Highlights
AVERAGE NO. OF LIKES
1 of your answers has been accepted
Awarded to li haitao on 20 Jul 2017
Provide your first answer ever to someone else's question
Awarded to li haitao on 20 Jul 2017
Solve all the problems in Introduction to MATLAB problem group
Awarded to li haitao on 18 Jan 2019
Solve all the problems in Cody5:Easy
Awarded to li haitao on 27 Nov 2018
Publish your first review
Awarded to li haitao on 09 Oct 2019
Solve all the problems in Divisible by x
Awarded to li haitao on 16 Nov 2018
Solve all the problems in Cody Challenge
Awarded to li haitao on 22 Oct 2018
Solve all the problems in Draw Letters problem group
Awarded to li haitao on 10 Oct 2018
Solve Project Euler problems using Matlab
Awarded to li haitao on 27 Sep 2018
Solve all the problems in Matrix Manipulation I
Awarded to li haitao on 16 May 2018
Create a problem
Awarded to li haitao on 12 Dec 2017
Be the first to solve a problem
Awarded to li haitao on 04 Dec 2017
Feeds
inverse function of zscore?
Give you an exmaple: >> load('lawdata.mat') >> [Z,gpamean,gpastdev] = zscore(gpa); >> gpa2=Z*gpastdev+gpamean; >> ...
10 years ago | 2
| accepted
You can also select a web site from the following list
Americas
- América Latina (Español)
- Canada (English)
- United States (English)
Europe
- Belgium (English)
- Denmark (English)
- Deutschland (Deutsch)
- España (Español)
- Finland (English)
- France (Français)
- Ireland (English)
- Italia (Italiano)
- Luxembourg (English)
- Netherlands (English)
- Norway (English)
- Österreich (Deutsch)
- Portugal (English)
- Sweden (English)
- Switzerland
- United Kingdom (English)
Asia Pacific
- Australia (English)
- India (English)
- New Zealand (English)
- 中国
- 日本Japanese (日本語)
- 한국Korean (한국어)