counter
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I=[1 0;1 1;1 0;0 0;0 1;1 1;........90bits]S=[0 1]now i need to calculate bit error =(counter/I);
i need to compare S with I using counter
1 Comment
Rick Rosson
on 24 Jun 2011
I do not understand what you are asking. What is "counter"? What does "S" represent? I assume that "I" is a 90 x 2 matrix (or is it 45 x 2) where each row is the outcome of two binary experiments, and there are 45 or 90 total trials. Is that correct?
Answers (1)
Paulo Silva
on 24 Jun 2011
Why repeating the question, you could and should edit your previous one.
s=[0 1];
I=[0 0;1 1;1 0;0 1;1 0;0 0; 1 0; 1 1; 0 0]
counter=0;
for n=1:size(I,1)
if I(n,:)==s
counter=counter+1;
else
%nothing to be done, just included the else for fun :)
end
end
counter
3 Comments
Paulo Silva
on 24 Jun 2011
bit error by your example that might not be correct is given by
Berror=(counter/I)
maybe you want this BError=counter/size(I,1) but this gives the opposite, maybe you want BError=1-counter/size(I,1) thus when all rows from I are equal to s (no error) you get BError=0
for the plot, BError is a constant plot(1:size(I,1),BError)
Sorry if all my assumptions aren't correct but you provide no details and I'm no expert in signal processing
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