extruct non zeros values and put into a short matrics

A =

0 0 0 0 5 0 0 8 0 0 0 0 8

0 0 0 5 0 0 0 8 0 0 0 0 9

0 0 0 5 0 0 0 7 0 0 0 0 8

0 0 0 0 5 0 0 0 8 0 0 0 9

0 0 0 6 0 0 0 8 0 0 0 0 9

0 0 0 5 0 0 0 7 0 0 0 0 8

0 0 0 8 0 0 0 8 0 0 0 0 9

I want to extruch a small matrics (with 3 columns) containing only non zeros values

Results:

 5  8  8
 5  8  9
 5  7  8
 5  8  9
 6  8  9
 5  7  8
 8  8  9

 ho I can do this smartly?

thanks

[Image Analyst]

To do it smartly and robustly, you'd check to make sure that there are the same number of zeros in each row. If there aren't you'd need to decide how to handle that, for example, take the first or last three

threeValues = find(oneRow~= 0, 3, 'first'); % Could be empty, 1, 2, or 3 at most.
if length(threeValues) == 3 .... etc.

Answer 1

[Azzi Abdelmalek]

out=cell2mat(arrayfun(@(x) A(x,A(x,:)~=0),(1:size(A,1))','un',0))

%or

n=size(A,1);
B=zeros(n,3);
for k=1:n
  B(k,:)=A(k,A(k,:)~=0);
end
B

[The Matlab Spot]

this is good...

out=cell2mat(arrayfun(@(x) A(x,A(x,:)~=0),(1:size(A,1))','un',0))

[Azzi Abdelmalek]

Not necessary, the second using for loop is slightly faster then arrayfun