why when I use mvrnd to generate random vectors from a multivariate normal I always get small numbers in absolute value ?
1 view (last 30 days)
Show older comments
Hi, why when I use mvrnd to generate random vectors from a multivariate normal I always get small numbers in absolute value (not larger than 4 or 5)? E.g.
mu=[0 0];
sigma=[1 0.4; 0.4 1];
r=10000; %number of simulated unobservables
epsilon=mvnrnd(mu,sigma,r);
Thanks
0 Comments
Accepted Answer
Vaclav Rimal
on 11 Dec 2013
The width of the distribution is ruled by the diagonal elements of sigma. If you want larger absolute values, try scaling sigma, e.g.
sigma = [10 4; 4 10];
2 Comments
Vaclav Rimal
on 11 Dec 2013
Edited: Vaclav Rimal
on 11 Dec 2013
But when the variances are v=1.0, the standard deviations of both vectors are supposed to be sqrt(v)=1.0, so there is only a little probability that a value exceeds the number 5 you mentioned. (99.7 % should have absolute values less than 3*sqrt(v), which you can test by sum(abs(epsilon)<3).) You simply cannot have v=1.0 and large numbers in the result.
More Answers (0)
See Also
Categories
Find more on Random Number Generation in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!