Sort columns by maximum value?

Having trouble with this one, how do I sort columns by the maximum value contained within them (must be a single line command)?

For example I have the following matrix:

5      -2  3
-10  6  2
0  0  1

The correct output should be:

3  5  -2
2  -10  6
1  0  0

I have narrowed it down to involving the max(x) command which returns the list of maximal values for each column as such:

5  6  3

But how can I then number these values in ascending order without first sorting them? e.g:

2  3  1

If I could do that then it would be simple to reorder from there. Again this problem seems easy using temporary variables but I have to do it as a single line. Any help appreciated.

Answer 1

[Azzi Abdelmalek]

We can make it simple

y=x(:,sortrows([max(x);1:size(x,2)]',1)*[0;1])

[Andrei Bobrov]

+1

Answer 2

[Sean de Wolski]

x = [5      -2  3
    -10  6  2
     0  0  1]

[~,idx] = sort(max(x));
y = x(:,idx)

[Sean de Wolski]

Personally, I would never recommend doing this operation in a single line because it will just obfuscate it. If you really need to, there's probably a way using arrayfun but it'll look hideous and be unreadable.

Or you could just stack them together :)

[~,idx] = sort(max(x));y = x(:,idx)

Answer 3

[Azzi Abdelmalek]

x=[5      -2  3
  -10  6  2
  0  0  1];
y=x(:,setdiff(accumarray(max(x)',(1:size(x,2))'),0,'stable'))

[Andrei Bobrov]

y=x(:,nonzeros(accumarray(max(x)',(1:size(x,2))')));

Answer 4

[Andrei Bobrov]

with subsref

y = x(:,subsref(sortrows([max(x)',(1:size(x,2))'],1),struct('type','()','subs',{{':',2}})))