I want to create a random matrix?

Help me!
I want to create a random matrix HM (3,5), it satisfies the following conditions:
1. The value of HM is a nonnegative integer from 0 to 4.
2. The total value of the elements in a row is less than or equal to 5.
Thank you very much!

3 Comments

Wayne King
Wayne King on 29 Dec 2013
Edited: Wayne King on 29 Dec 2013
0 is not a positive integer. And why a nonnegative integer from 0 to 4? How can you select a 4 and possibly get a sum less than or equal to 3?
Ok, sorry. a nonnegative integer from 0 to 4 with the total value of the elements in a row is less than or equal to 6.
you can help me

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 Accepted Answer

Amit
Amit on 29 Dec 2013
okay .. an approach would be rejection method .. be careful .. for extremely large matrix this will be a bad idea .. tmp1= randi([0 c],a*100,b); tmp1=tmp1(sum(tmp1,2)<=d); HM=tmp1(1:a,:);

6 Comments

the idea here is to create a large matrix(that's why 100*a) and the reject the values which don't qualify the conditions ..
When I for example: a = 5, b = 8, c = 4, d = 8, the matrix size is HM (5,1)?
you can also use while loop as well for rejection method, but that will be slower..
correction: tmp1=tmp1(sum(tmp1,2)<=d,:)
OK. Thanh you very much!
Hello
The code above has the following disadvantages: When b is large and d is small, the matrix tmp1 to satisfy the conditions will be the number of rows <a. So HM matrix will fail. For example:
tmp1= randi([0 3],5*10000,50);
tmp1=tmp1(sum(tmp1,2)<=10,:);
HM=tmp1(1:5,:)
It will error: Index exceeds matrix dimensions.
Are you using the loop, you can just help me. Thanks.

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More Answers (1)

Amit
Amit on 29 Dec 2013
write down all possible ways to get 3 or less than 3 using integers 0-4 like [1 0 0 0 0] [1 1 0 0 0] etc.... pick one of the matrix for each row (randomly) and then use randperm to reorder them.

13 Comments

Amit
Amit on 29 Dec 2013
Edited: Amit on 29 Dec 2013
lets say you get 20 possible matrixes stored in comb(20,5) then:
temp1 = randi (20,10,1); HM=comb(temp1,:); for I=1:10 HM(I,:)=HM(I,randperm(5)); end
Sorry, I couldn't change it to code tags as I was replying from phone.
You can write a script to perform this matrix with a nonnegative integer from 0 to 4 with the total value of the elements in a row is less than or equal to 6.
Undefined variable comb.
Error in Untitled2 (line 2)
HM=comb(temp1,:);
Amit
Amit on 29 Dec 2013
Edited: Amit on 29 Dec 2013
comb is the matrix you'll make. comb in your case will be [1 0 0 0 0; 1 1 0 0 0; 1 1 1 0 0;2 0 0 0 0; 2 1 0 0 0;3 0 0 0 0]
Thank you, but it looks like this is complex and crafts. You can just give me the brief command to create this matrix.
Amit
Amit on 29 Dec 2013
Edited: Amit on 29 Dec 2013
the final code for your case:
comb=[1 0 0 0 0;1 1 0 0 0;1 1 1 0 0;2 0 0 0 0;2 1 0 0 0;3 0 0 0 0]; temp1 = randi (6,10,1); HM=comb(temp1,:); for I=1:10 HM(I,:)=HM(I,randperm(5)); end
You have way without using comb because the matrix HM large size, you can not list all cases of comb.
you changed the question from original post and how is 3×5 matrix matrix huge? and to make comb matrix, just make a code based on how you'll do it if you were suppose to do this on paper.
Because the matrix in my program HM large size. I just gave an example of a small matrix HM with such constraints.
Then can you state your real problem please?
Pham
Pham on 29 Dec 2013
Edited: Pham on 29 Dec 2013
I want to create a random matrix HM (a,b), it satisfies the following conditions:
1. The value of HM is a nonnegative integer from 0 to c.
2. The total value of the elements in a row is less than or equal to d.
Above example is only one case.
Can you help me. Thank you very much!
does b, c and d have any correlation? like in the example case, you have b=c+1, d=c+1
b, c and d are any integers

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