Varying parameters in if statement

Hi! I would like to create a conditional statement where the parameters of my if statement is changing. Is it possible to vary the parameters in the if statement?
Here is an example:
x10=1;
i=10;
word='x';
if ('%s%d~=1',word,i)
v='not working'
end
I tried this one but it is not working, any suggestion on how to make it work?

 Accepted Answer

Here is the closest I can get to the code that I think you wanted:
x10=1;
i=10;
word='x';
% Create a "pass/fail" variable that will be tested.
eval(sprintf('PF = %s%d~=1;',word,i))
% Do the test
if PF
v = 'not working'
end

3 Comments

Guessing you can avoid some of this awkward code by using cell array variables such as
x{10}
rather than names like x10, but maybe not, because it looks like even the text of the variable name can vary.
Yes, both the variable and digit vary
Is there an alternative way wherein I don't need to store it to another variable? I'm using this code for my GUI wherein I will need that code to compare to almost 3000 variables. If I add more variables, it will make the real time clock in my GUI hang.
x10=1;
i=10;
word='x';
% Create a "pass/fail" variable that will be tested.
eval(sprintf('if %s%d~=1, v = ''not working''; disp(v); end ',word,i))
If you don't actually need to display the 'not working' text, then you can get rid of the
disp(v)
statement inside the eval() statement.

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More Answers (1)

Mischa Kim
Mischa Kim on 9 Mar 2014
Edited: Mischa Kim on 9 Mar 2014
Something like:
mynum = 2; % change to mynum = 1
x10 = 1;
word = 'x';
i = 10;
if (eval(genvarname(strcat(word,num2str(i)))) == mynum)
fprintf('x10 is %d\n', mynum);
else
fprintf('x10 is not %d\n', mynum);
end

1 Comment

Is there an alternative way wherein I don't need to store it to another variable? I'm using this code for my GUI wherein I will need that code to compare to almost 3000 variables. If I add more variables, it will make the real time clock in my GUI hang.

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Asked:

on 9 Mar 2014

Edited:

on 9 Mar 2014

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