guys.i finally can find a way.i used a block combination that takes count sample times.if my file works properly the counter doesn't reach the upper limit and if it works bad the counter reaches the upper limit. thank to my friend @the cyclist for his inspiring idea. at the first i got the clock signal and compared with zero.the boolean signal divided by itself and make a count to add the counter.you should use a memory block to add the signal of summation with the output of memory block that form a feedback system.the output of system divide by an integer.for my case i use 100.this is for avoiding reaching to upper bound of memory block buffer.and finally i compared the divide block with an integer.if the signal exceed the threshold the compare block send a signal to stop block. excuse me if my explanation wasn't good.my english isn't good. i apologize for my mistakes.
how can i stop simulation if it takes so long?
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hi guys how can i stop simulation with a block or something else if time to complete the simulation takes so long.the simulation is part of a code and this must be automatic. thank you with regard
Accepted Answer
the cyclist
on 21 Apr 2014
Edited: the cyclist
on 21 Apr 2014
If your simulation has some kind of looping structure in it (e.g. for loop), then you could use the tic/toc functions something like this:
x = 0;
% Simulation starts here. (Using a while loop that is always true, to mimic a long-running simulation.)
tic
while true
x = x+1;
if toc > 5
break
end
end
last_x = x
This "simulation" will halt if it runs for more than about 5 seconds.
More Answers (1)
Magdi Mosa
on 10 Oct 2018
Edited: Magdi Mosa
on 10 Oct 2018
yes thank you. it works well, for simplification the following picture may elaborate the idea
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