image derivatives using gaussian
5 views (last 30 days)
Show older comments
Hi, this is the function I have for calculating the image derivatives. Please help me understand this code as I am new to this field. If anyone could give me some links to understand this concept, I'll be greatful. some doubts that i have -
- Why are we using ndgrid here?
- What are the directions 'x', 'y', 'xx', ('xy', 'yx'), 'yy' here?
- And how and why does the formula for this gaussian change according to the directions?
- Why are we using imfilter at the end?
function D =calc_image_derivatives(I,sigma,direction)
[x,y]=ndgrid(floor(-3*sigma):ceil(3*sigma),floor(-3*sigma):ceil(3*sigma));
switch(direction)
case 'x'
DGauss=-(x./(2*pi*sigma^4)).*exp(-(x.^2+y.^2)/(2*sigma^2));
case 'y'
DGauss=-(y./(2*pi*sigma^4)).*exp(-(x.^2+y.^2)/(2*sigma^2));
case 'xx'
DGauss = 1/(2*pi*sigma^4) * (x.^2/sigma^2 - 1) .* exp(-(x.^2 + y.^2)/(2*sigma^2));
case {'xy','yx'}
DGauss = 1/(2*pi*sigma^6) * (x .* y) .* exp(-(x.^2 + y.^2)/(2*sigma^2));
case 'yy'
DGauss = 1/(2*pi*sigma^4) * (y.^2/sigma^2 - 1) .* exp(-(x.^2 + y.^2)/(2*sigma^2));
end
D = imfilter(I,DGauss,'conv','replicate');
0 Comments
Answers (0)
See Also
Categories
Find more on Multirate Signal Processing in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!