LSB in audio stegnography
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    Muhammad fayyaz
 on 28 Apr 2014
  
    
    
    
    
    Commented: Walter Roberson
      
      
 on 31 Mar 2016
            % Embed message length in the first 16 samples 
% (I don't understand how.  Can any one explain?)
str = dec2bin(length(message),16);  
if length(message) < length(y)  
  for a = 1 : length(str)  
    y(a, nbits-1) = str(a);
  end
else 
  disp('error')
end
I don't understand how they are embedding here. Please help me.
1 Comment
Accepted Answer
  Walter Roberson
      
      
 on 28 Apr 2014
        They are converting the message length to 16 text-coded binary locations, and are taking the resulting 16 bits and using them to replace the least significant bits of 16 successive text-coded binary representations.
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More Answers (2)
  Muhammad fayyaz
 on 29 Apr 2014
        2 Comments
  Walter Roberson
      
      
 on 29 Apr 2014
				Assume that the original signal has been converted into binary by using dec2bin(). dec2bin() returns an array of characters, each one being the character '0' or the character '1'. Then y(a,nbits-1) is a straight forward replacement of one element of the array with one element of the character vector "str".
Somewhere after this section of code, you will find a call to bin2dec(y) . That operation will take the character array y and convert the representation back into decimal numbers.
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