Matrix betweenness - how to?

Bg: I have three matrices of the same size. A, B and C. Most elements in these matrices are the same except a few.

Ask: I want to deduce a 4th matrix D (the same size) that gives element "1" whenever corresponding element of B is between that of A and C. Otherwise 0 for that element.

Clarification: I don't care too much if it isn't "1" and it is an actual subtraction between element A and C. I just need a 0 if B's element is not between that of A and C.

Preferably I want a matlab/ opencv way to do this.

[José-Luis]

What have you tried so far?

 condition = (A < B && B < C)

[DotFrammie]

I needed element wise comparison and store each element result into answer matrix. So the answer is a matrix of binary results but not a scalar binary itself. Thanks for the comment.

[José-Luis]

 A < B & B < C

Answer 1

[dpb]

You asked for my utility function iswithin --

>> type iswithin

function flg=iswithin(x,lo,hi)
% returns T for values within range of input
% SYNTAX:
%  [log] = iswithin(x,lo,hi)
%      returns T for x between lo and hi values, inclusive
  flg= (x>=lo) & (x<=hi);

This version is inclusive...the alternative of isbetween is exclusive--

function flg=isbetween(x,lo,hi)
% returns T for values between range of inputs
% SYNTAX:
%  [log] = isbetween(x,lo,hi)
%      returns T for x between lo and hi values, exclusive
  flg= (x>lo) & (x<hi);

I've yet another that has optional flags for each bound being inclusive or not.

In use it's simply for your case --

d=iswithin(b,a,c);

The assumption is that all(a(:)<=b(:))==TRUE. If your data aren't necessarily ordered (so the comparison could be in either direction), simply use--

    d=iswithin(b,min(a,c),max(a,c));

to get the ordering right for the limit arguments LO/HI.

[DotFrammie]

Thanks you dpb very much for the answer!! What if the assumption isn't true and the three matrices are as follows...

Clarification Example: If A, B and C are as follows:

A= [12 24 18; 34 45 35; 08 12 34];
B= [13 26 18; 45 01 38; 80 10 34];
C= [10 34 18; 45 45 35; 90 09 34];

I want to calculate a D using openCV or matrices manipulations so that it can be

D= [0 1 1; 1 0 0; 1 0 1];

[dpb]

OK, you definitely want the iswithin version of inclusive comparison and to use the min()/max() on the two limits arrays as outlined...

>> iswithin(B,min(A,C),max(A,C))
ans =
   0     1     1
   1     0     0
   1     1     1
>>

I think the middle entry, third row in your D is in error, however, as 10 is certainly between 9 and 12.