How do I get the indexes of a symmetrical logical matrix without getting repetitions of those indexes?

I have a matrix of logical values that is symmetrical. All are zeros except for a few 1's. I need to get the indexes of the 1's without having two different iterations of the indexes due to the symmetrical nature of the matrix. How would I do this?

[David Haydock]

   0   0   0   0   1   0   0   0
   0   0   0   1   0   0   0   0
   0   0   0   0   0   0   1   0
   0   1   0   0   0   0   0   0
   1   0   0   0   0   0   0   0
   0   0   0   0   0   0   0   1
   0   0   1   0   0   0   0   0
   0   0   0   0   0   1   0   0

Here is the matrix. I need the row and column index of each one. I can do that. But, for example, I will have (1,5) and (5,1). How do I ensure I only have one of them?

Answer 1

[Matt J]

[I,J]=find(yourMatrix);
keep=(J>=I);

I=I(keep);
J=J(keep);

[David Haydock]

Thanks very much Matt! Works like a charm.