intersect between the second column of cell array A (for all rows) and the first column of cell array B (for all rows)

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I want to intersect between the second column of cell array A (for all rows) and the first column of cell array B (for all rows).
I tried
but an error is resulting:
Error using intersect
Too many input arguments.
What I am doing wrong?
Thank you.

Accepted Answer

Steven Lord
Steven Lord on 8 Nov 2021
Let's make some sample cell arrays with animal names. [I'm assuming your cell arrays contain text data.]
animals = {'dog','cat','fish','horse'};
rng default
A = animals(randi(numel(animals), 5, 2))
A = 5×2 cell array
{'horse'} {'dog' } {'horse'} {'cat' } {'dog' } {'fish' } {'horse'} {'horse'} {'fish' } {'horse'}
B = animals(randi(numel(animals), 5, 2))
B = 5×2 cell array
{'dog' } {'dog' } {'horse'} {'cat' } {'horse'} {'horse'} {'cat' } {'horse'} {'horse'} {'horse'}
Instead of using {} to extract the elements of the second column of A and the first column of B (which would result in a comma-separated list), use () to extract the columns themselves (which results in smaller cell arrays.)
[C, IA, IB] = intersect(A(:, 2), B(:, 1)) % Use () to extract a sub-cell array
C = 3×1 cell array
{'cat' } {'dog' } {'horse'}
IA = 3×1
2 1 4
IB = 3×1
4 1 2

More Answers (2)

Jon on 8 Nov 2021
Edited: Jon on 8 Nov 2021
The problem is that A{:,2} and B{:,1} are not returning arrays but instead multiple answers. So somthing like this:
>> A = {1,2,3;4,5,6}
A =
2×3 cell array
{[1]} {[2]} {[3]}
{[4]} {[5]} {[6]}
>> A{:,2}
ans =
ans =
you could try
That is surround the results by square brackets to consolidate them into arrays. If this doesn't help then please copy an example piece of code that shows the problem, and in particular defines your A and B cell arrays, and I can try to help you further

dpb on 8 Nov 2021
This may or may not be possible with simple syntax depending upon the content of the cell arrays...if it can work,
The curlies {} return a comm-separated list; the [] will gather that into a vector if the cell content is not nested.
The simpler solution in that instance would be to use cell2mat() on A and B first and get rid of the cell arrays; there wouldn't be any need to keep pure numeric data as a cell array to begin with.
If it is nested, then you'll have to dereference the underlying content appropriately.

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