# For Loop and if statement

1 view (last 30 days)
Zain Abbas on 10 Nov 2021
Edited: Kevin Holly on 10 Nov 2021
Can someone explain how can use for loop for a data where i have 4 columns as shown below and for each of 3 categories i want to sum the the corresponding x y and z values?
x y z category
9 6 7 1
7 8 6 2
9 1 2 1
5 7 8 3
8 5 1 2

Kevin Holly on 10 Nov 2021
Edited: Kevin Holly on 10 Nov 2021
m = [9 6 7 1
7 8 6 2
9 1 2 1
5 7 8 3
8 5 1 2];
a=[];
for i=1:3
a = [a; [sum(m(m(:,4)==i,1:3),1) i]];
end
a
a = 3×4
18 7 9 1 15 13 7 2 5 7 8 3
Breakdown:
m(:,4)==1
ans = 5×1 logical array
1 0 1 0 0
The above creates a logical array of all row in the matrix (m) where the 4 column is equal to 1.
The specific elements within the matrix were selected as m(rows,columns). A colon (:) was used for rows, indicating to select all rows, which in this case was 5. This could also be describe as an array from 1 to 5 or 1:5. For the columns, only the 4th was selected, thus you end up with m(:,4).
m(:,4)
ans = 5×1
1 2 1 3 2
Now, let's look at the first three columns 1 through 3.
m(:,1:3)
ans = 5×3
9 6 7 7 8 6 9 1 2 5 7 8 8 5 1
Let's use the logical array to select only the one where the 4th column in matrix m is equal to one.
m(m(:,4)==1,1:3)
ans = 2×3
9 6 7 9 1 2
Now, let's sum the columns.
sum(m(m(:,4)==1,1:3),1)
ans = 1×3
18 7 9
Now, let's add the 4th column back by concatenating with a bracket.
[sum(m(m(:,4)==1,1:3),1) 1]
ans = 1×4
18 7 9 1
Finally, replace the 1 with an i and create a for loop to calculate for catergories 1 through 3. The variable a is created to hold the results in a single matrix. Each result is appended as a row.
a=[];
for i=1:3
a = [a; [sum(m(m(:,4)==i,1:3),1) i]];
end
a
a = 3×4
18 7 9 1 15 13 7 2 5 7 8 3

R2021a

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