Line prob at o2

image2= o2{120}

[Cris LaPierre]

original question

Can anyone help me to understand in the line 5 why it is using 136?

i2 = imread('00020361.bmp');
m2 = i2(201:808,201:808);
n2 = imbinarize(m2,0.6);
o2 = mat2cell(n2,[32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32],[32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32]);
image2= o2{136}
c = normxcorr2(image1,image2);
figure, surf(c), shading flat
[ypeak, xpeak] = find(c==max(c(:)));
yoffSet = ypeak-size(image1,1);
xoffSet = xpeak-size(image2,2);
figure
imshow(image2);
imrect(gca, [xoffSet+1, yoffSet+1, size(image1,2),size(image1,1)]);

Answer 1

[Cris LaPierre]

It is using linear indexing to extract the 136th cell from o2. Linear indexing counts down the rows, column by column. Item 136 is in the cell in the 3rd row, 8th column. You can learn more here and here.

You can use ind2sub to convert a linear index to the more familiar (m,n) syntax.

i2 = imread('https://www.mathworks.com/matlabcentral/answers/uploaded_files/802529/00020361.bmp');
m2 = i2(201:808,201:808);
n2 = imbinarize(m2,0.6);
o2 = mat2cell(n2,[32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32],[32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32,32]);

[row,col] = ind2sub(size(o2),136)

row = 3

col = 8

[Image Analyst]

Must be nice to be on staff and have the unreleased Mind Reading Toolbox. I have no idea how you figured that out from a post that said only "image2= o2{120}" and nothing else.

Anyway, the FAQ might also help the user understand cell arrays.

https://matlab.fandom.com/wiki/FAQ#What_is_a_cell_array.3F

[Cris LaPierre]

Looks like most of the original question has been edited away. Added a comment back in with the original question so that the answer makes sense.