Matlab recommends to replace histc by histcounts. However, I obtain different results:
x=[123.1900 120.9395 120.9395 120.9395 112.6711 415.4625];
y=[112.6711 120.9395 123.1900 415.4625]
which yields
K>> histc(xRd(:),auxVecX)
ans =
1
3
1
1
but
histcounts(xRd(:),auxVecX)
ans =
1 3 2
How can I handle histcounts so that the outputs are the same?

1 Comment

Sorry, I meant histc(x,y) versus histcounts(x,y).

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 Accepted Answer

The result differ by the way the last bin is handed in both function. To get the same result you must change the last edge to Inf for histc
x=[123.1900 120.9395 120.9395 120.9395 112.6711 415.4625];
y=[112.6711 120.9395 123.1900 415.4625];
xRd = x;
auxVecX = y;
auxVecX(end) = Inf
auxVecX = 1×4
112.6711 120.9395 123.1900 Inf
histc(xRd(:),auxVecX)
ans = 4×1
1 3 2 0

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