What is wrong in line 101?

4 views (last 30 days)
MR JUSTIN ACHARJEE Sumanta
Commented: Steven Lord on 20 Jan 2022
Calculate internal stresses for maximum and minimum bending moments and plot their distribution on the cross section.
%%Q1f
clc; clear; close all
disp('Simply Supported Beam');
% Data input section
disp(' ');
L = input('Length of beam in meter = ');
disp(' ');disp('Type 1 for point load, Type 2 for udl')
Type = input('Load case = ');
if Type == 1
disp(' ');
W = input('Load applied in kN = ');
disp(' ');
a = input('Location of Load from left end of the beam in meter = ');
c = L-a;
R1 = W*(L-a)/L; % Left Support Reaction.
R2 = W*a/L; % Right Support Reaction.
else
disp(' ');
W = input('Uniformly distributed load in kN/m = ');
disp(' ');
b = input('Length of udl in meter = ');
disp(' ');
cg = input('C.G of udl from left end of the beam in meter = ');
a = (cg-b/2);
c = L-a-b;
R1 = W*b*(b+2*c)/(2*L); % Left Support Reaction.
R2 = W*b*(b+2*a)/(2*L); % Right Support Reaction.
end
% Discretization of x axis.
n = 1000; % Number of discretization of x axis.
delta_x = L/n; % Increment for discretization of x axis.
x = (0:delta_x:L)'; % Generate column array for x-axis.
V = zeros(size(x, 1), 1); % Shear force function of x.
M = zeros(size(x, 1), 1); % Bending moment function of x.
% Data processing section
if Type == 1
for ii = 1:n+1
% First portion of the beam, 0 < x < b
V(ii) = R1;
M(ii) = R1*x(ii);
% Second portion of the beam, b < x < L
if x(ii) >= a
V(ii) = R1-W;
M(ii) = R1*x(ii)-W*(x(ii)-a);
end
end
x1 = a;
Mmax = W*a*(L-a)/L;
else
for ii = 1:n+1
% First portion of the beam, 0 < x < a
if x(ii) < a
V(ii) = R1;
M(ii) = R1*x(ii);
elseif a <= x(ii) && x(ii)< a+b
% Second portion of the beam, a < x < a+b
V(ii) = R1-W*(x(ii)-a);
M(ii) = R1*x(ii)-W*((x(ii)-a)^2)/2;
elseif x(ii) >= (a+b)
% Second portion of the beam, a+b < x < L
V(ii) = -R2;
M(ii) = R2*(L-x(ii));
end
end
x1 = a+b*(b+2*c)/(2*L);
Mmax = W*b*(b+2*c)*(4*a*L+2*b*c+b^2)/(8*L^2);
end
disp(' ');disp (['Left support Reaction' ' = ' num2str(R1) ' ' 'kN'])
disp(' ');disp (['Left support Reaction' ' = ' num2str(R2) ' ' 'kN'])
disp(' ');disp (['Maximum bending moment' ' = ' num2str(Mmax) ' ' 'kNm'])
figure
subplot(2,1,1);
plot(x, V, 'r','linewidth',1.5);
grid
line([x(1) x(end)],[0 0],'Color','k');
line([0 0],[0 V(1)],'Color','r','linewidth',1.5);
line([x(end) x(end)],[0 V(end)],'Color','r','linewidth',1.5);
title('Shear Force Diagram','fontsize',16)
text(a/2,V(1),num2str(V(1)),'HorizontalAlignment','center','FontWeight','bold','fontsize',16)
text((L-c/2),V(end),num2str(V(end)),'HorizontalAlignment','center','FontWeight','bold','fontsize',16)
axis off
subplot(2,1,2);
plot(x, M, 'r','linewidth',1.5);
grid
line([x(1) x(end)],[0 0],'Color','k');
line([x1 x1],[0 Mmax],'LineStyle','--','Color','b');
title('Bending Moment Diagram','fontsize',16)
text(x1+1/L,Mmax/2,num2str(roundn(Mmax,-2)),'HorizontalAlignment','center','FontWeight','bold','fontsize',16)
text(x1,0,[num2str(roundn(x1,-2)) ' m'],'HorizontalAlignment','center','FontWeight','bold','fontsize',16)
axis off
  4 Comments
MR JUSTIN ACHARJEE Sumanta
text(x1+1/L,Mmax/2,num2str(roundn(Mmax,-2)),'HorizontalAlignment','center','FontWeight','bold','fontsize',16)
I am having error in this line.
Steven Lord
Steven Lord on 20 Jan 2022
Please show us the the full and exact text of the error and/or warning messages (all the text displayed in red and/or orange in the Command Window when you run your code.)

Sign in to comment.

Answers (1)

Yongjian Feng
Yongjian Feng on 20 Jan 2022
Your file has no line 101. Only 94 lines in total.
Tried some sample input data, and it works without error. What inputs are needed to reproduce the error?
  2 Comments
MR JUSTIN ACHARJEE Sumanta
text(x1+1/L,Mmax/2,num2str(roundn(Mmax,-2)),'HorizontalAlignment','center','FontWeight','bold','fontsize',16)
This line is showing error.
Yongjian Feng
Yongjian Feng on 20 Jan 2022
It must be related to the inputs you gave. Tried some random inputs and it works.
  1. Give us the inputs you use to reproduce the error.
  2. Paste the error here.

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!