How to plot a function dependent on no. of iterations, provided it plots till nth iteration where n is the number where the function is converged?
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Hello All,
I am trying to plot a function vs no. of iterations. In the for loop, i have given the convergence condition, but I am unable to plot for f(x) vs no. iterations (till convergence). Please help.
Its of the form:
for m=1:n
pu(m)=(-1)^m)/((2*m)+1))*(exp(-((2*m)+1)))
e = e+pu;
if (abs(pu)/e)<(10^(-6)) %convergence check
break
end
end
hold all
plot(1:n,pu,'linestyle','none','marker','*')
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Accepted Answer
VBBV
on 28 Jan 2022
Edited: VBBV
on 29 Jan 2022
n= 10;
e = 0;
for m=1:n
pu(m)=(-1)^m/((2*m)+1)*(exp(-((2*m)+1)))
e = e+pu(m);
if (abs(pu(m))/e)>(10^(-6)) %convergence check
break
end
end
hold all
plot(1:n,pu,'linestyle','-','marker','.')
Check the convergence condition
7 Comments
VBBV
on 29 Jan 2022
legend(mrkr{cidx},legendInfo)
Put this line inside the inner for loop. After legendInfo. Everytime the inner for loop exits, it's over written with initial values for mrkr and clr index.
VBBV
on 29 Jan 2022
Edited: VBBV
on 29 Jan 2022
u=zeros(n,npoints); % change also This line in beginning
u(m,cidx)=pu(m);
hold all
plot(1:m,u(1:m,cidx),'linestyle','none','marker',mrkr{cidx},'Color',clr{cidx})
You also need to change these two lines inside the for loop. As you can see the u value is dependent on pu which is again varying with each outer iteration of for loop.
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