Time series syntax question

Hi everyone, I'm using a template for a homework assignment in MATLAB. I'm having trouble with a section that seems to require time series, but I can't find any info on this particular type. The code is: ts(i,1) =%fill in here . I've never seen the ts(i,1) syntax before, and can't find any info on it anywhere. Can anyone explain to me what this means?

2 Comments

Did you read this? Looks like a starting point to me.
I read these, but none of them go over this syntax, unless I just don't recognize it, which is also very likely.

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 Accepted Answer

ts(i, 1) refers to the element of the ts array in the i'th row and the first column. Assuming i is a single number , like 5 or whatever, then ts(i,1) would be assigned a single number, like 73 or whatever.
ts(i, 1) = 73;
If i = 5, this would assign ts(5,1) a value of 73.
If i is an array of numbers or array of logicals then ts(i,1) would assign a bunch of rows in the first column. Like if i were [2,4,8], ts(i,1) would need to take 3 numbers, like
ts(i, 1) = [22,34,88];
This would assign element ts(2,1) to 22, element ts(4,1) to 34, and assign element ts(8,1) to 88. I hope that explains it better.

More Answers (1)

Youssef  Khmou
Youssef Khmou on 26 Nov 2014
ts(i,1) means performing calculation of the elements of first column of matrix ts, ts(i,2) means the ith element on the second column, ( use other variable instead of i, i is the imaginary number )

2 Comments

Stefan
Stefan on 26 Nov 2014
Edited: per isakson on 26 Nov 2014
So what would I even put after the equals sign? I'm still confused. This is the rest of the code leading up to that point, if this helps any:
function out = main()
close all;
pars=[4 10 1 20 1 20];
k1=pars(1);
k2=pars(2);
k3=pars(3);
k4=pars(4);
k5=pars(5);
k6=pars(6);
init=[10 10 10];
steps = 500000;
ts= zeros(steps+1,4);
ts(1,2:4) = init;
a=ts(1,2);
b=ts(1,3);
c=ts(1,4);
for i = 2:(steps+1)
lmd1 = k1*a*b;
lmd2 = c*k2;
lmd3 = a*k3;
lmd4 = k4;
lmd5 = b*k5;
lmd6 = k6;
rate = [lmd1 lmd2 lmd3 lmd4 lmd5 lmd6];
lmd = sum(rate);
p= cumsum(rate)/lmd;
U = rand(1,2);
Here you assign an array of double to a variable named, ts. Confusing!

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