I can solve this problem by those code but how can i solve this problem by using loop?

error = 1;

while error

mukim = input('Please select mukim (A = Pulai, B = Tebrau, C = Kota Tinggi): ','s');

switch mukim

case 'A'

v = 45;

error = 0;

case 'B'

v = 55;

error = 0;

case 'C'

v = 50;

error = 0;

otherwise

fprintf('\n Wrong selection, please type A, B or C \n\n')

end

end

h = input ('Chimney height (meter) from the earth surface: ');

t = 0;

i=1:100;

t=t+i;

z = h + (80/15)*(v + ((80*9.81)/15))*(1-exp((-15/80)*t))-(((80*9.81)/15)*t);

[maxz,correspondindtimeforz]=max(z);

maxtime=t(correspondindtimeforz);

fprintf('\nThe particles achieve peak elevation altitude = %5.2f meter after %i seconds release from chimney.\n\n', maxz, maxtime)

Answer 1

[David Hill]

Don't understand your question. You are using a loop.

l=[45 55 50];
while 1
  mukim = input('Please select mukim (A = Pulai, B = Tebrau, C = Kota Tinggi): ','s');
  if ismember(mukim,'ABC')
      v=l(ismember('ABC',mukim));
      break;
  end
  fprintf('\n Wrong selection, please type A, B or C \n\n');
end

[CHEE KIN CHUM]

Sorry for not clarify the question clearly , what i really want to ask is how to determine the peak elevation altitude and it coressponding time by using while loop instead of using max function

[David Hill]

Just need to do some math.

l=[45 55 50];
while 1
  mukim = input('Please select mukim (A = Pulai, B = Tebrau, C = Kota Tinggi): ','s');
  if ismember(mukim,'ABC')
      v=l(ismember('ABC',mukim));
      break;
  end
  fprintf('\n Wrong selection, please type A, B or C \n\n');
end
h = input ('Chimney height (meter) from the earth surface: ');
c = 15;
g = 9.81;
w = 80;
tmax = w/c*log((v*c+w*g)/w/g);%seting derivative == 0 and solving for t
zmax = h + (w/c)*(v + w*g/c)*(1-exp(-c/w*tmax))-w*g/c*tmax;