Need help for these two commands
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These are two lines
dif = length(sig) - length(ADSR);
x = cat(2, ADSR, zeros(1,dif));
What is purpose of zeros(1,dif) Plz explain
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Accepted Answer
Wayne King
on 22 Sep 2011
It is appending (padding) zeros on the end of ADSR so that the total length of x is the length of the signal, sig:
length(ADSR)+ (length(sig)-length(ADSR))
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More Answers (2)
Fangjun Jiang
on 22 Sep 2011
It creates a 1 by dif matrix and all its value is zero.
cat(2, ADSR, zeros(1,dif)) is the same as [ADSR, zeros(1,dif)]
I want to give a caution on using function length().
LENGTH(X) returns the length of vector X. It is equivalent
to MAX(SIZE(X)) for non-empty arrays and 0 for empty ones.
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Walter Roberson
on 22 Sep 2011
The code is constructing a vector that pads ADSR with 0s to be the same length as sig is.
Another way of doing this would be:
x = zeros(size(sig));
x(1:length(ADSR)) = ADSR;
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