Compare a string against list of other strings

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Hello,
I would like to understand how to compare a user-inputted string against a list of other strings. I have some extremely verbose code that does work but I am convinced there must be a more elegant solution.
I paste example code below. I am trying to compare a "data rate" against some "permissible rates". Can anyone advise? Thank you.
clear; clc;
data_rate = '288'; % user input
permissible_rates = {'128';'256';'512'}; % validate input against this
check_rate = NaN(size(permissible_rates)); % set up empty array
% Go through the permissible rates, and see if the data rate string is the
% same of any of the permissible rates. If yes, output is 1. If no, output
% is 0
for i=1:length(permissible_rates)
check_rate(i)=strcmp(data_rate,permissible_rates{i});
end
% if there are no 1s in the array, the user input is invalid
if ismember(1,check_rate) ~= 1
error('You didn''t choose a correct data rate');
end
% otherwise continue
disp('You choose a correct data rate, congratulations')
  1 Comment
KSSV
KSSV on 1 Apr 2022
Are you sure they are strings? Why they are strings? Happily you can have them as numbers right?

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Answers (1)

KSSV
KSSV on 1 Apr 2022
data_rate = '288'; % user input
permissible_rates = {'128';'256';'512'}; % validate input against this
idx = contains(permissible_rates,data_rate)
idx = 3×1 logical array
0 0 0
  5 Comments
rkoz575
rkoz575 on 4 Apr 2022
Thank you Steven for the comprehensive answer. I should have realised that contains would fail in the case you mention (where 288 is somewhere in the text). "matches" is a better function to use!
If you submit this as an answer I will accept it.
ajay kumar
ajay kumar on 6 Jul 2022
data_rate = '288';
someRates = {'2889','1288', '72883', '288'};
find(matches(someRates,data_rate))
ans = 4
It will give right index with idx

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