extract small vector from large vector

b=[1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
a=zeros(3,1);
c=([a;b]);
d=(c(1,1):c(6,1));
e=(c(4,1):c(9,1));
please suggest me the way how can i write the code for vector d and e.
i want d vector as; d= [0;0;0;1;2;3] and
vector e as ; e=[1;2;3;4;5;6]

 Accepted Answer

b = [1;2;3;4;5;6;7;8;9;10;11;12;13;14;15];
a = zeros(3,1);
c = [a; b]
c = 18×1
0 0 0 1 2 3 4 5 6 7
d = c(1:6,1) % ",1" not necessary since c only has one column
d = 6×1
0 0 0 1 2 3
e = c(4:9) % ",1" omitted
e = 6×1
1 2 3 4 5 6

8 Comments

You're welcome!
sir, just tell me is it correct? if wrong please correct me.
utdelt=([1;2;3;4;5;6;7;8;9;10;11;12;13;14;15]);
nodof=3;
for i=1
for n=1:1:5
if n==1
Utdelt=([zeros(nodof,1); (utdelt(1:nodof,i))]);
eval(['Utdelt',num2str(n),'=[zeros(nodof,1); (utdelt(1:nodof,i))]']);
else
Utdelt=utdelt([(1+(n-2)*nodof):(6+(n-2)*nodof),(i)]);
eval(['Utdelt',num2str(n),'=[utdelt([(1+(n-2)*nodof):(6+(n-2)*nodof,(i)])]']);
end
end
I can't say whether it's correct since I don't know what it's supposed to do, but I would make Utdelt a matrix:
utdelt=([1;2;3;4;5;6;7;8;9;10;11;12;13;14;15]);
nodof=3;
Utdelt = zeros(6,5);
for i=1
for n=1:1:5
if n==1
Utdelt(:,n) = [zeros(nodof,1); utdelt(1:nodof,i)];
else
Utdelt(:,n) = utdelt( 1+(n-2)*nodof : 6+(n-2)*nodof , i );
end
end
end
Utdelt
Utdelt = 6×5
0 1 4 7 10 0 2 5 8 11 0 3 6 9 12 1 4 7 10 13 2 5 8 11 14 3 6 9 12 15
sir i want to extract Utdelt as a column vector of 6X1.
But you calculate Utdelt in a loop that iterates 5 times.
If you want each Utdelt as a 6x1 column vector then how you had it was basically fine. Here is your code again, except without the eval statements, without all the unnecessary parentheses, fixing the indentation, and adding a missing end at the end.
utdelt=([1;2;3;4;5;6;7;8;9;10;11;12;13;14;15]);
nodof=3;
for i=1
for n=1:1:5
if n==1
Utdelt = [zeros(nodof,1); utdelt(1:nodof,i)];
else
Utdelt = utdelt( 1+(n-2)*nodof : 6+(n-2)*nodof , i );
end
Utdelt
% presumably, you would do something with Utdelt at this point
end
end
Utdelt = 6×1
0 0 0 1 2 3
Utdelt = 6×1
1 2 3 4 5 6
Utdelt = 6×1
4 5 6 7 8 9
Utdelt = 6×1
7 8 9 10 11 12
Utdelt = 6×1
10 11 12 13 14 15
thank you sir, in this loop i am calculating the f_s but when i am seeing the result the output is comin wrong.
utdelt=([1;2;3;4;5;6;7;8;9;10;11;12;13;14;15]);
Ktts=rand(6,6);
nodof=3;
for i=1
for n=1:1:5
if n==1
Utdelt = [zeros(nodof,1); utdelt(1:nodof,i)];
else
Utdelt = utdelt( 1+(n-2)*nodof : 6+(n-2)*nodof , i );
end
Utdelt
% presumably, you would do something with Utdelt at this point
end
f_s=Ktts*Utdelt;
end
That uses the value of Utdelt that was calculated for n=5. Previously calculated Utdelt values, i.e., for n=1 through n=4, are not used. Maybe that's what's wrong.

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on 8 Apr 2022

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