Find indexes in cell array

Hi all,

i have 2 arrays one containing all my values (even duplicates) and one containing the unique elements.

My goal is to find the index of my values based on the index of the unique elements

R = [2 ,1 ,	1 ,	2 ,	4 , [1,3] ,	[1,3] ,	4 ,	[1,3] ,	[2,5] ,	[2,5] , 4]
C= [2 ,	1 ,	4 ,	[1,3] , [2,5]]

Vectors [1,3] should be treated as 1 unique element, not as 1 and 3

If its easier we can work with letters

R1=['2B' , '1A' , '1A' , '2B' , '1D' , '1A+1C' ,'1A+1C' , '1D' , '1A+1C' , '1B+1E' , '1B+1E', '1D']
C1=['1A' , '2B' , '1A+1C' , '1D' , '1B+1E']

In both cases i expect to get an array

idx = [2, 1, 1, 2, 4, 3, 3, 4, 3, 5, 5, 4]

The order is important, idx should be in the same order of the original R/R1 vector.

I tried find and a bit of arrayfun but couldnt get it to work

Thank you so much in advance

Answer 1

[Jon]

R1={'2B' , '1A' , '1A' , '2B' , '1D' , '1A+1C' ,'1A+1C' , '1D' , '1A+1C' , '1B+1E' , '1B+1E', '1D'}
C1={'1A' , '2B' , '1A+1C' , '1D' , '1B+1E'}
[~,Locb] = ismember(R1,C1)

[Jon]

Note curly braces to make a cell array, if you use square brackets all of the elements will just be concatenated into one long character array

[Davide Bordin]

thank you

[Jon]

Glad that it helped, good luck with your project