dynamic naming of structures

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DrK
DrK on 16 May 2022
Commented: DrK on 17 May 2022
If I have a variable x='name', how can I use x to build a structure with name 'name' that looks like:
name.a
name.b
No need to tell me about the hazards of dynamic variable naming.
Thanks.

Accepted Answer

DrK
DrK on 17 May 2022
Actually, found my own answer:
x = 'name';
eval(sprintf('%s = struct;',x));
This creates a structure named 'name' and one can use the same eval format to add fields to it later.
  7 Comments
DrK
DrK on 17 May 2022
Thanks for the light reading. I think I am going to take this in the direction of indexing instead.
Thanks again for your help.

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More Answers (2)

James Tursa
James Tursa on 16 May 2022
Would it be acceptable to use x as a dynamic fieldname instead of the top level variable name? E.g.,
v.(x).a
v.(x).b

DrK
DrK on 17 May 2022
Not really. I know about the paranthesis around field names, but it creates another level of structure. The problem is that if I am creating the structure names inside my program, I don't know how to create the structures using those names.
Thanks for your response.

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