help on graph (w/o common matrix plotting built-in functions)

Dear all,

based on a matrix of zeros and ones, let's say 10 x 365 (10 years a 365 days), I would like to plot a '-' for a one and leave the position blank ' ' for a zero.

Thus, the graph should e.g. look like:

....

------ --- --- ---- ---- ------ ----- --

-------- ------ --------------- -----------

------ -- ---------- --------- ---------

----- --------------- ------ ---------- -

.....

Any hint appreciated.

Answer 1

[Les Beckham]

In that case, maybe something like this will get you close.

A = randi(2,10,365)-1;
x = 1:size(A,2);
y = size(A,1):-1:1;
for i = 1:size(A,1)
    A(i,:) = A(i,:)*y(i);
end
A(A==0) = NaN;
for i = 1:size(A,1)
    line(x, A(i,:), 'Marker', '_', 'linestyle', 'none', 'MarkerSize', 0.1)
end

Answer 2

[Les Beckham]

A = randi(2,10,365)-1

A = 10×365

1 1 1 1 1 1 1 1 0 1 0 1 1 0 1 1 0 0 0 0 0 0 1 1 0 1 1 0 1 0 1 0 0 1 0 1 1 0 0 0 1 0 0 1 0 0 1 1 0 0 0 0 0 1 1 1 1 1 0 0 0 1 1 1 1 0 1 1 0 1 0 1 1 1 1 0 1 1 0 0 0 0 1 1 0 0 0 1 1 1 1 0 0 0 1 0 0 1 0 1 1 1 1 0 1 1 0 0 0 0 1 0 0 0 1 1 1 1 0 0 0 1 0 0 0 0 1 1 0 1 0 0 0 1 1 0 1 1 0 0 0 0 1 1 1 0 0 1 1 1 0 0 0 1 0 0 1 0 1 0 1 1 0 0 1 1 0 0 1 1 1 0 0 0 1 1 0 1 0 1 1 0 1 0 0 1 0 1 0 0 1 0 1 0 0 1 1 0 1 0 1 0 0 0 0 0 0 0 1 1 1 1 1 0 0 1 1 1 1 1 1 1 0 0 1 0 1 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 0 1 0 0 0 0 0 0 1 0 1 1 0 0 1 1 1 1 1 0 0 0 0 0 1 0 0 1 0 0 1 1 1 0 1 1 1 0 0 1 0 1 0 1 0 0 1 0 0 0 1 1 1 0 1 0 0 1

str = repmat(' ', size(A));
str(A==1) = '-';
disp(str)

-------- - -- --      -- -- -   -    ------ -  --- --- --   -   - -    -      -   --  ---  - --- -   --  - -- -- -- --- ----  -- --- ----  - -   -  - --  - ------- - - - - - ----    --- -  --  --- - --  -  ---   -  -- - -   -  ----- ---   ---- ------- -   - -  -     --- -  -------  ---- --         --  - - - -- -  -- -   - -    -  -- -    ----  -- -- - --  ---   -
-  - --   -  -  --     -----      -   - ----  ---- --    -  -- ------- --- -  -   - - ---   ----   -  - - - - -- -  - ----  -          -  -   ------  ------  - ---   --- --  --  -     -    - -- - - --   --- -- - -----   -- - - -- ---- ----  - --  -  -  - --- - -  --  -   - -- -    -- -    - -  - -    --     -- - ---  --     ---  -  --  - -   -  ---      - -- -- -
 ---- -- - ---- --    --   ---  ---     -- -- -  - - -----  ---- -   - ----  -    - ---- -  ---  - -- ---     -- - ---  --- ----- --  --   --- -  --    -   ---  -  ---  -  --- ---   ------  -- -  -- -  - -----      - --- ----- -- -    - -   ------ ---- -      -             --  ---  -----  -   -  --- -- -- -    -     -----  -  - - -  -----   - -  - ----- --  -  - 
-   -  - ---- --    -   ----    --- -  ------ - -   --   -  -- ---- -    - ---- --- ---- ---  - --- - - - - -   -- ------   ----  --- -  --- - -- ------ --- --    -- - --   --    - -----  ---  -    -   - ---------    -   - ----   - ---  -        -    -- -----   ---  --- -   --------    ----  -  -  -------  -- -    -   ---- -   - --   - -  ----     --- - -  -  - -
 -    -- -   -- --    ---  ---  -  --   -    -- ---- -  -   --  - --- -- -  - --- --- -   -  -    -  -   ----- -----  -- - --    -- ---    -  --         -- -  -   -  ----  -  -- --- -  -- - --  -- ----- ----------   -    ---- --  -- - --    - - - ----    -----  -    --- - -- -  ------ -  ---- --     - - -  - -   - -- -  ---  --- --   ---- -   - -   - -  - -  -   
   -  - - --  --  ---   -- - ---- - ---  -  ----   -  - - --    ---- - --- -   -    -  --- - ----- -- ----  ---- -  -  ----- -- - - - --  - -  ---  - -- -- - -    -  ---  -- -  -     -- -   --  -  - - -- --    -   -      -- --- -  - -   - - - - - ----   -     --    - ----- -   --- - -  - - -  --  - --   -  --- -- -   - -  -  --   --- ---  - -- ---  -- -- ---- ---
- -  - -  - -  -- - -       -- - ----------- - -  - ------  - - -   ---    -- -  -  -  ---   -- -- -  -  --- -   -  --  -- ---- -  ---- -   --  -   ------- -   - -    -   ----     ----- --   ---- - ---- ----  - --  -  -    -       --  - - - - - -    --- -- -  --- ----    --  ------- --       -- - - - - - -    - --- - --   --- --- -  - -  -----  -  -- -   -- -   -
---  -------  - --   -- -  --    ---     -  -  -- ---   --- -- --- -- ------ --   - --- ---   --   -      ---- -      -      --   ----  -- -  ---  - -- -  -    - ---   --  --------- -- -   ---  - - -    --- - ---- -- -  - --- -  -  -- ----- - - -- -    --- --- -  - -  - - --- -   -- ---- --  ---  -  -- --   - --- ------- - --    --- -- - -------      -   -   - - 
-  -      - --  -----     -  - -  - -  --    - -     -   -- -  - -- -- ---- -- --      -- --  -   --- --  -  -- - ---   -    ------  - -  ----  -- -- -   ----- -    - - -- --  -   -- - - -----        -      -- -   --- - --- -  - - - --     --  --- - - -  --   - --- ---  --- -    ----   -  -  - ----  - ----  --  - -   -- -  --    --    -  -- ----  - -  -   - -   -
  --- ---  - - -  -   --- -  -- --    -  ---  - ---   -- - ----         -------  --    ---  --- - -   -- -  - -     - - -- - -  ----    --  --  ---     -- ---  - - -  ---  - -- - --  ---  -       --- -- -    -   ---- - -  -  --- - -   -- ---- ---   -  -- -- -- --  --  ---   ---    -      - --     -- ---  ---  ---- -- -- -----   -   --    -   -  -- -----  -  -----

[Steven Lord]

A = randi([0 1], 5, 5)

A = 5×5

1 1 0 0 0 1 0 1 1 1 1 1 1 0 0 1 0 0 1 0 0 0 1 0 1

B = ' -';
B(A+1)

ans = 5×5 char array
    '--   '
    '- ---'
    '---  '
    '-  - '
    '  - -'

[Les Beckham]

@Steven Lord

How clever! I'm suprised that that works. I would have never thought to index into a 1x2 array with a larger index array.

[Steven Lord]

The size of the index array doesn't matter for linear indexing. What matters are the values in that array.

Answer 3

[Patrick Laux]

excellent already, but actually I thought about having a real figure with xaxis and yaxis. Sorry that I was not very clear here.

[Steven Lord]

A = randi([0 1], 5, 5)

A = 5×5

1 0 0 1 1 1 1 1 1 1 1 0 1 0 1 0 1 1 1 0 0 1 0 1 1

spy(A)

If you really want dashes:

figure
spy(A, '_')

Answer 4

[DGM]

In the spirit of ridiculousness, here is my attempt:

% random binary data
data = randi([0 1],10,10)

data =

1 1 0 0 1 1 1 1 0 0

0 0 0 1 0 1 1 1 1 1

0 0 0 1 1 0 0 0 1 0

1 1 1 1 0 1 0 0 1 0

0 1 0 1 0 1 1 0 1 1

0 1 0 1 0 0 1 1 1 0

0 0 1 0 1 0 1 0 0 0

0 0 0 0 0 1 1 0 0 1

1 0 0 0 1 1 0 1 0 1

0 1 1 0 0 1 0 1 0 1

% convert to char data (space and full-width crossbar)
charmap = char([32 196]);
chardata = charmap(data+1)

chardata =

10×10 char array

'ÄÄ ÄÄÄÄ '

' Ä ÄÄÄÄÄ'

' ÄÄ Ä '

'ÄÄÄÄ Ä Ä '

' Ä Ä ÄÄ ÄÄ'

' Ä Ä ÄÄÄ '

' Ä Ä Ä '

' ÄÄ Ä'

'Ä ÄÄ Ä Ä'

' ÄÄ Ä Ä Ä'

% construct an image by flowing char glyphs into a rectangular box
charsize = [8 8]; % depends on the selected font
datasize = size(chardata);
tsize = [NaN datasize(2)*charsize(2)+charsize(2)/2]; 
outpict = textblock(chardata(:)',tsize,'font','compaq-8x8','tightwidth',true,'hardbreak',true);

% display the image with character-centered tickmarks
xrange = 0.5:datasize(1)+0.5;
yrange = 0.5:datasize(2)+0.5;
imagesc(xrange,yrange,1-outpict)
colormap(gray)

Alternatively, instead of using a full crossbar, you can just use

charmap = ' -';

and get

Bear in mind those are different random data. The point is that the bars don't touch.

This uses a few tools from MIMT, namely textblock() and imstacker().

Answer 5

[Patrick Laux]

great answers! Thank you very much, very helpful

Answer 6

[Voss]

data = randi([0 1],10,30)

data = 10×30

0 0 1 1 0 1 1 1 1 0 1 0 1 0 0 1 1 1 0 1 1 1 1 1 0 1 1 0 0 0 0 1 1 0 1 0 1 1 1 1 1 0 0 1 1 0 0 1 0 1 1 1 1 0 1 0 0 0 1 0 1 1 1 1 0 1 1 0 0 0 0 0 1 1 0 1 1 0 0 1 0 1 0 0 1 0 0 1 1 1 0 1 1 0 1 0 0 1 0 0 0 0 1 1 0 1 0 1 0 0 0 1 1 1 1 1 1 0 0 1 0 1 0 1 0 1 0 1 0 1 1 0 0 1 1 1 0 1 1 1 1 0 0 1 0 1 0 0 0 1 0 1 1 0 0 0 1 1 1 1 0 0 0 0 0 0 0 1 1 0 1 1 0 0 1 0 1 1 1 0 0 0 0 1 1 0 1 1 0 0 0 0 0 0 0 0 0 1 1 1 0 1 1 0 1 0 0 0 1 1 0 1 0 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 1 1 0 0 0 0 0 0 0 1 0 1 0 1 0 1 1 0 0 0 0 0 1 1 0 1 0 0 0 1 1 1 0 1 1 0 1 1 0 1 1 1 1 1 0 0 0 1 0 1 1 0 1 1 0 0 1 1 1 0 0 0 0 1 0 1 0 0 1 1 0 1

imshow(1-data)