How to name variables in a loop?

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I have 3 structures with name
Time1, Time2 and Time3 but I want to rename them in a loop such that it can be rennamed such as
A.Time1,B.Time2,C.Time3
and then within Time1, Time2 and Time3 there are 2 vectors each i.e., Time1.v1 and Time1.v2; Time2.v1 and Time2.v2; Time3.v1 and Time3.v2 respectively. I also want to rename them in a loop as
A.Time1.v1 and A.Time1.v2; B.Time2.v1 and B.Time2.v2; C.Time3.v1 and C.Time3.v2
  7 Comments
Stephen23
Stephen23 on 4 Jun 2022
Edited: Stephen23 on 4 Jun 2022
"so for plots say I want to plot"
Aaah, so your question is an example of this:
Rather than telling us about your attempted solution using ugly dynamic variable names, you should explain your actual task/goal/problem that you are trying to solve.
"I am asking this as I have to generate 100 of plots and I cannot repeat the code"
Why not? Use indexing. Every array can be accessed using indexing, including container arrays (e.g. tables, cell arrays and structure arrays). What is stopping you from storing your data in arrays and using indexing?
Muhammad Qaisar Fahim
Muhammad Qaisar Fahim on 4 Jun 2022
You are right. My explanation is not good. Let me try again. I run simulation and as a result of simulation I get results in the form of structure. Say structure1. Then I change some parameters and run my simulation again Now I again get results in the form of structure. Say structure2. Now variables names inside thses structures are same but their values will be different. Their could be n number of structures and the number of variables inside the structure are 100 or more each. Now I want to plot some variables of those n structures on top of each other to compare. I an thinking of a solution to name the structures before the loop such that I only give n (i.e., number of structures I want to compare) and my plots are generated and I dont need to write 100 lines for 100 structures. I hope the question is clear now ?

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Accepted Answer

Stephen23
Stephen23 on 4 Jun 2022
n = 100;
C = cell(1,n);
for k = 1:n
.. run your simulation here
C{k} = the results of your simulation
end
  2 Comments
Muhammad Qaisar Fahim
Muhammad Qaisar Fahim on 4 Jun 2022
The issue is I have to stick with the structure. I cannot change the format.
Stephen23
Stephen23 on 4 Jun 2022
"The issue is I have to stick with the structure. I cannot change the format."
Every cell of C contains your structure. The structure "format" does not change.
Note that you can also create a single structure array (assuming compatible sizes and fields):
S = [C{:}]

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