Variable Number of Arguments
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Abdul Hanan Wali
on 22 Jun 2022
Commented: Image Analyst
on 22 Jun 2022
following is a function which unable to run in my matlab. Kindly repair the problem and tell me.
function out = print_num(format, varagin)
out = ' ' ;
argindex = 1;
skip = false;
for ii = 1: length(format)
if skip
skip = false;
else
if format(ii) ~= '%'
out(end+1) = format(ii);
else
if ii + 1> length(format)
break;
end
if format(ii+1) =='%'
out(end+1) ='%';
else
if argindex >= nargin
error(' not enough input arguments');
end
out = [ out num2str(varagin{argindex},format(ii:ii+1))];
argindex = argindex +1;
end
skip = true;
end
end
end
end
1 Comment
Image Analyst
on 22 Jun 2022
What problem? You forgot to tell us what the problem is.
Don't call your variable "format" since that's a built-in function and can't be used as a variable name. Call it "userFormat" or something else.
And you also forgot to tell us how you called the function. How many arguments did you pass in and what were they? If you pass in, say 8 arguments, how do you parse them into separate variables? Are you expecting variables in a certain order?
If you have any more questions, then attach your data and code to read it in with the paperclip icon after you read this:
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