why the plot figure is empty?
4 views (last 30 days)
Show older comments
claudia francis
on 24 Jun 2022
Answered: Yash Srivastava
on 28 Jun 2022
i'm trying to plot funcion of t that has sigma of n in it.
it's not showing any errors
Ts = 4;
f = @(t) sinc((t-n*Ts)/Ts);
x1n = sinc(n*4);
x2n = (sinc(n*4/12)).^2;
x3n = cos(pi*n*4/12);
syms n
xr1 = @(t) symsum(x1n.*f,n,-13,13);
syms n
xr2 = @(t) symsum(x2n.*f,n,-13,13);
syms n
xr3 = @(t) symsum(x3n.*f,n,-13,13);
figure(1)
fplot(xr1,[-13 13])
title("x_1[n]")
figure(2)
fplot(xr2,[-13 13])
title("x_2[n]")
figure(3)
fplot(xr3,[-13 13])
title("x_3[n]")
1 Comment
Dyuman Joshi
on 24 Jun 2022
sinc(0) throws off an error in symbolic usage
syms x1n(n)
x1n(n) = sinc(n*4)
x1n(0)
Accepted Answer
Yash Srivastava
on 28 Jun 2022
Hi Claudia
I have modified your code a little bit. Instead of using function handle, we can directly use the expression treating n and t of "syms" type.
Also, sinc(x) = sin(pi*x) / pi*x, will result into "division by 0" error. Therefore, in xr1, xr2 and xr3 I have changed the range of n from [-13 13] to [1 13] to avoid that error.
clear;
syms n t
Ts = 4;
f = sinc((t-n*Ts)/Ts);
x1n = sinc(n*4);
x2n = (sinc(n*4/12)).^2;
x3n = cos(pi*n*4/12);
xr1 = symsum(x1n.*f,n,1,13);
xr2 = symsum(x2n.*f,n,1,13);
xr3 = symsum(x3n.*f,n,1,13);
figure(1)
fplot(xr1,[-13 13])
title("x_1[n]")
figure(2)
fplot(xr2,[-13 13])
title("x_2[n]")
figure(3)
fplot(xr3,[-13 13])
title("x_3[n]")
0 Comments
More Answers (0)
See Also
Categories
Find more on Calculus in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!