Creating a string with Permutation

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hamzah khan
hamzah khan on 15 Jul 2022
Answered: Voss on 15 Jul 2022
Hi,
I have a short question, I am creating a string with a loop but I cannot do the permutation/combination correctly
here is my code
Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
C_ext = nan*zeros(length(Axes_name),length(fold_2));
for i=1:length(Axes_name)
for j=1:length(fold_2)
leg{sub2ind(size(C_ext),i,j)} = [Axes_name{i} ' ' fold_2{j}];
end
end
I am trying to make combinations like this:
sint0.2 BCA
sint0.2 BPCA
sint0.2 DLA
sint0.2 DLCA
sint0.5 BCA
sint0.5 BCPA
sint0.5 DLA
sint0.5 DLCA
...
and so on, but i am not getting it correctly.Does any know what changes i should do

Accepted Answer

Adam Danz
Adam Danz on 15 Jul 2022
Edited: Adam Danz on 15 Jul 2022
I believe this is what you're working toward.
Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
str = compose('%s %s', string(Axes_name), string(fold_2)')
str = 3×4 cell array
{'sint0.2 BCA'} {'sint0.2 BPCA'} {'sint0.2 DLA'} {'sint0.2 DLCA'} {'sint0.5 BCA'} {'sint0.5 BPCA'} {'sint0.5 DLA'} {'sint0.5 DLCA'} {'sint0.7 BCA'} {'sint0.7 BPCA'} {'sint0.7 DLA'} {'sint0.7 DLCA'}
If you want a column vector,
str(:)
ans = 12×1 cell array
{'sint0.2 BCA' } {'sint0.5 BCA' } {'sint0.7 BCA' } {'sint0.2 BPCA'} {'sint0.5 BPCA'} {'sint0.7 BPCA'} {'sint0.2 DLA' } {'sint0.5 DLA' } {'sint0.7 DLA' } {'sint0.2 DLCA'} {'sint0.5 DLCA'} {'sint0.7 DLCA'}

More Answers (2)

Paul
Paul on 15 Jul 2022
Hi hazmah,
Is this what you're looking for?
Axes_name = string({'sint0.2';'sint0.5';'sint0.7'})
Axes_name = 3×1 string array
"sint0.2" "sint0.5" "sint0.7"
fold_2 = string({'BCA';'BPCA';'DLA';'DLCA'})
fold_2 = 4×1 string array
"BCA" "BPCA" "DLA" "DLCA"
result = reshape(Axes_name.' + " " + fold_2,[],1)
result = 12×1 string array
"sint0.2 BCA" "sint0.2 BPCA" "sint0.2 DLA" "sint0.2 DLCA" "sint0.5 BCA" "sint0.5 BPCA" "sint0.5 DLA" "sint0.5 DLCA" "sint0.7 BCA" "sint0.7 BPCA" "sint0.7 DLA" "sint0.7 DLCA"

Voss
Voss on 15 Jul 2022
Axes_name = {'sint0.2';'sint0.5';'sint0.7'};
fold_2 = {'BCA';'BPCA';'DLA';'DLCA'};
You can change the size of C_ext to be length(fold_2)-by-length(Axes_name), since you want to cycle through the fold_2 values first in leg. (Swap j and i where they're used in sub2ind as well.)
C_ext = nan*zeros(length(fold_2),length(Axes_name));
for i=1:length(Axes_name)
for j=1:length(fold_2)
leg{sub2ind(size(C_ext),j,i)} = [Axes_name{i} ' ' fold_2{j}];
end
end
leg = leg.'
leg = 12×1 cell array
{'sint0.2 BCA' } {'sint0.2 BPCA'} {'sint0.2 DLA' } {'sint0.2 DLCA'} {'sint0.5 BCA' } {'sint0.5 BPCA'} {'sint0.5 DLA' } {'sint0.5 DLCA'} {'sint0.7 BCA' } {'sint0.7 BPCA'} {'sint0.7 DLA' } {'sint0.7 DLCA'}
However, you can create matrices of indices i and j using meshgrid or ndgrid, and construct leg at once using strcat:
[i,j] = meshgrid(1:numel(Axes_name),1:numel(fold_2));
leg = reshape(strcat(Axes_name(i),{' '},fold_2(j)),[],1)
leg = 12×1 cell array
{'sint0.2 BCA' } {'sint0.2 BPCA'} {'sint0.2 DLA' } {'sint0.2 DLCA'} {'sint0.5 BCA' } {'sint0.5 BPCA'} {'sint0.5 DLA' } {'sint0.5 DLCA'} {'sint0.7 BCA' } {'sint0.7 BPCA'} {'sint0.7 DLA' } {'sint0.7 DLCA'}

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