Phasor Diagram for three phase sinusoidal signal

How to plot the phasor diagram for three phase signal?

eg:

clc;

t = 0:100e-6:0.1;

f = 50;

w = 2*pi*f;

Vm = 1;

R = Vm*sin(w*t);

Y = Vm*sin(w*t - 120(pi/180));

B = Vm*sin(w*t - 240(pi/180));

I would appreciate if someone can answer this, i.e., how to represent the phasor diagram for RYB with vector magnitude and each phase displaced by 120 degree apart.

Answer 1

[Hari]

Hi Bharath,

As per my understanding, you want to plot a phasor diagram for a three-phase signal.

You can calculate the real and imaginary components for each signal and then use the “quiver” function to plot the vectors.

1. Use the magnitude and the phase angle of the signal to calculate the real and imaginary parts:

    % Calculating the real and imaginary components of the three-phase signal
    Real = Mag * cos(Phase);
    Imag = Mag * sin(Phase);

2. Plot the function using “quiver”

    % Plotting the phasor diagram using "quiver" function
    quiver(start_x, start_y, Real, Imag);

“quiver” function takes the starting point coordinates (start_x, start_y), and the real and imaginary components of each vector as arguments. You can also specify other parameters such as colours, labels, etc. By plotting each your “R”, “Y”, “B” signals in this way, you can get the phasor diagram for the three-phase signal, whose phases are 120 degrees displaced.

Refer to the below documentation to learn more about “quiver” function in MATLAB.

Quiver or vector plot - MATLAB quiver (mathworks.com)