Facing difficulty in finding the error saying Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters."

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Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters." here is the code. can't find where the mistake is. Need help.
function f=secant(xi)
f = x(i)^6-x(i)-1;
%f = @(x) x(i)^6-x(i)-1;
x(1)=2;
x(2)=1;
e=10^-3;
n=50;
for i=1:n-2
x(i+2)=x(i+1)-(f(x(i+1))*(x(i+1)-x(i)))/(f(x(i+1))-f(x(i)));
fprintf('x%d=%.10f\n',i,x(3))
if abs(x(3)-x(2))<e
break
end
x(i)=x(i+1);
x(i+1)=x(i+2);
end
plot(x(i),f(x(i)),'b')
disp([i x(i) f(x(i)) abs(x(i)-x(i+1))])
end

Answers (2)

Torsten
Torsten on 6 Sep 2022
f = @(x)x.^6-x-1
instead of
f = x(i)^6-x(i)-1;

Cris LaPierre
Cris LaPierre on 6 Sep 2022
You are trying to index a function input variable in the function declaration. This is not allowed. Instead, create a new variable name in the function declaraion,
function f = secant(xIn)
and when calling your function, index you input variable.
out = secant(x(i))
To make this change, you will likely have to update how you use x inside your function.
  1 Comment
Cris LaPierre
Cris LaPierre on 6 Sep 2022
Edited: Cris LaPierre on 6 Sep 2022
You have updated your problem description. Your original description gave the function declaration and code as pasted below, which does give the error message you provided.
% calling syntax (I added this to recreate the error message)
x = rand(1,5);
out = secant(x)
% original function code
function f=secant(x(i))
Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.
f = x(i)^6-x(i)-1;
x(1)=2;
x(2)=1;
e=10^-3;
n=50
for i=1:n-2
x(i+2)=x(i+1)-(f(x(i+1))*(x(i+1)-x(i)))/(f(x(i+1))-f(x(i)));
fprintf('x%d=%.10f\n',i,x(3))
if abs(x(3)-x(2))<e
break
end
x(i)=x(i+1);
x(i+1)=x(i+2);
end
plot(x(i),f(x(i)),'b')
disp([i x(i) f(x(i)) abs(x(i)-x(i+1))])
end

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