Function that produce an uniform random numbers for loop error
3 views (last 30 days)
Show older comments
Hi i'm having an issue in my for loop
i',m trying to make a function that produce an uniform random numbers but no matter what i adjust i keep getting the same error
clear
clc
%N=input('sequence_length')
N=5000
MinSec = fix(clock);
seed = 100*MinSec(5) + MinSec(6);
Urand = myrandi(seed,N);
%b
%Y=ones(size(Urand));
subplot(2,1,1)
hist(Urand)
%% Task 1: : the Linear Congruential Generator (LCG)
v = rand(1,N);
%u=u./max(u);
subplot(3,2,2);
hist(v,100);
title(subplot(2,1,2),'Uniform random: rand()');
%Function that produce an uniform random numbers
%Using the technic of LCG r(k) = [lambda*r(k-1)]modulo(P)
function Urand = myrandi(seed,sequence_length)
la=65539
N=sequence_length;
P=2^31
%change N accordingly
%part a
Urand=zeros(1,N);
Urand(1)=seed;
for i=2:N
Urand(i)= mod(la*seed(i-1),P);
end
Urand=Urand/65539;
%printing genetrated vector, after dividing by 6655
if N<=50 %will print numbers only
if N<=50
disp(['for N = ',num2str(N)])
disp(Urand)
end
end
end%function myrand
0 Comments
Accepted Answer
KSSV
on 14 Oct 2022
This line:
Urand(i)= mod(la*seed(i-1),P);
Your seed is a scalar, it has sinlge value. You are trying to extract more number by indexing it and treating it as a vector. This is the error.
Do you mean to use:
Urand(i)= mod(la*seed*(i-1),P);
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!