How do I copy fields name and their contents to another struct variable?

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Lets say that I have this code:
a=struct;
a(1).a='a1';
a(1).b='b1';
a(1).c='c1';
a(2).a='a1';
a(2).b='b1';
a(2).c='c1';
a(3).a='a1';
a(3).b='b1';
a(3).c='c1';
Now, I want to copy only a(2) to b(1) with its all fields. for example:
b=struct;
b(1)=a(2);
b(2)=a(3);
How can I do that?

Answers (1)

Jos (10584)
Jos (10584) on 23 Mar 2015
a(1).x = 1
a(2).x = 2
a(3).x = 3
b(1:2) = a(2:3) % Is this what you want? b(1) now equals a(2) ...
  2 Comments
ELI
ELI on 23 Mar 2015
If I do that, I get error:
Subscripted assignment between dissimilar structures.
Jess
Jess on 7 Mar 2017
What version of MATLAB are you using? The following works for me in 8.4.0.150421 (R2014b):
a=struct;
a(1).a='a1';
a(1).b='b1';
a(1).c='c1';
a(2).a='a2';
a(2).b='b2';
a(2).c='c2';
a(3).a='a3';
a(3).b='b3';
a(3).c='c3';
b(1:2) = a(2:3)
(Note that I changed the values slightly.)
Perhaps instead of
a(1).x = 1
a(2).x = 2
a(3).x = 3
you should write out x:
a(1).a = 1
a(2).a = 2
a(3).a = 3
It sounds like you're storing one thing in another wrong.

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