In order to code HDL, how to avoid using break statements in loops

Since I'm seeking for HDL code that doesn't allow the break, continue statement, I need help with the following code logic to stop the break statement from being executed.

case 1:

clc;
eps = 5;
x = 1:5;
y = zeros(5,1);
fprintf('%10s|%10s|\n----------+----------+\n','n','y(n)');

         n|      y(n)|
----------+----------+

for idx = 1:length(x)
    y(idx) = x(idx) + 1;
    if(y(idx) > eps)
        break;
    end
    fprintf('%10d|%10d|\n',idx,y(idx));
end

         1|         2|
         2|         3|
         3|         4|
         4|         5|

case : 2

clc;
eps = 5;
x = 1:5;
y = zeros(5,1);
fprintf('%10s|%10s|\n----------+----------+\n','n','y(n)');

         n|      y(n)|
----------+----------+

for idx = 1:length(x)
    y(idx) = x(idx) + 1;
    if(y(idx) > eps)
        idx = 1;
    end
    fprintf('%10d|%10d|\n',idx,y(idx));
end

         1|         2|
         2|         3|
         3|         4|
         4|         5|
         1|         2|

Because more iterations are being executed, case 2's results are incorrect.

Thank you!!

Answer 1

[Life is Wonderful]

I think i have the solution ,

x = 1:5;
eps = 5;
y = zeros(1,1);
fprintf('%10s|%10s|\n----------+----------+\n','n','y(n)');

         n|      y(n)|
----------+----------+

idx = 1;
while (y < eps)
    y = x(idx) + 1;
    fprintf('%10d|%10d|\n',idx,y);
    idx = idx + 1;
end

         1|         2|
         2|         3|
         3|         4|
         4|         5|

Any fresh suggestion for improvement is welcome, and I am open to it.