Unrecognized variable, want to create a list of variable

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Hello,
I'm trying to run an optimization model but I always get the error "Unrecognized function or variable 'c1_std'.
I want to call d = (c1_std, c2_std, c3_std) to run my optimization model and find the best parameters. How should I define d to call d(1)=c1_std in my different functions?
I'm not an expert in Matlab so please excuse me if my code is quite rude.
Thank you in advance.
Paul
muL = 2000;
sigL = 200;
R1 = 1-9.92*10^-5;
R2 = 1-1.2696*10^-4;
R3 = 1-3.87*10^-6;
d = [c1_std,c2_std,c3_std];
Sr1_min = sqrt(((((1.5-1)*muL)/norminv(R1))^2)-(sigL)^2);
Sr1_max = sqrt(((((2.5-1)*muL)/norminv(R1))^2)-(sigL)^2);
Sr2_min = sqrt(((((1.5-1)*muL)/norminv(R2))^2)-(sigL)^2);
Sr2_max = sqrt(((((2.5-1)*muL)/norminv(R2))^2)-(sigL)^2);
Sr3_min = sqrt(((((1.5-1)*muL)/norminv(R3))^2)-(sigL)^2);
Sr3_max = sqrt(((((2.5-1)*muL)/norminv(R3))^2)-(sigL)^2);
sqrt((((1.5-1)*muL)/norminv(R1)^2)-(sigL)^2)
norminv(R1)
lb = [Sr1_min,Sr2_min,Sr3_min];
ub = [Sr1_max,Sr2_max,Sr3_max];
A = [];
B = [];
Aeq = [];
Beq = [];
d0 = (lb+ub)/2;
fun = @(d) parameterfun(d,muL,sigL);
const = @(d) nonlcon(d,muL,sigL);
[d,fval] = fmincon(fun,d0,A,B,Aeq,Beq,lb,ub,const);
function Rs = parameterfun(d,muL,sigL)
muL = 2000;
sigL = 200;
R1 = 1-9.92*10^-5;
R2 = 1-1.2696*10^-4;
R3 = 1-3.87*10^-6;
d = [c1_std,c2_std,c3_std];
mu_Sr1 = muL+norminv(R1)*sqrt((sigL)^2+(d(1))^2);
mu_Sr2 = muL+norminv(R2)*sqrt((sigL)^2+(d(2))^2);
mu_Sr3 = muL+norminv(R3)*sqrt((sigL)^2+(d(3))^2);
Y1_mean = muL-mu_Sr1;
Y2_mean = muL-mu_Sr2;
Y3_mean = muL-mu_Sr3;
Y1_std = sqrt((d(1))^2+(sigL)^2);
Y2_std = sqrt((d(2))^2+(sigL)^2);
Y3_std = sqrt((d(3))^2+(sigL)^2);
Y_mean = [Y1_mean Y2_mean Y3_mean];
Y_std = [(Y1_std^2) (sigL)^2 (sigL)^2; (sigL)^2 (Y2_std)^2 (sigL)^2; (sigL)^2 (sigL)^2 (Y3_std)^2];
y = zeros(size(d));
Rs = mvncdf(y, Y_mean, Y_std);
end
function [c,ceq] = nonlcon(d,muL,sigL)
muL = 2000;
sigL = 200;
R1 = 1-9.92*10^-5;
R2 = 1-1.2696*10^-4;
R3 = 1-3.87*10^-6;
d = [c1_std,c2_std,c3_std];
c(1) = ns_min(1) - ((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2)))/muL);
c(2) = ns_min(2) - ((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2)))/muL);
c(3) = ns_min(3) - ((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2)))/muL);
c(4) = ((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2)))/muL) - ns_max(1);
c(5) = ((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2)))/muL) - ns_max(2);
c(6) = ((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2)))/muL) - ns_max(3);
c(7) = c_min(1) - (c1_std/((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2)))));
c(8) = c_min(2) - (c2_std/((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2)))));
c(9) = c_min(3) - (c3_std/((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2)))));
c(10) = (c1_std/((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2))))) - c_max(1);
c(11) = (c2_std/((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2))))) - c_max(2);
c(12) = (c3_std/((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2))))) - c_max(3);
format long
c
ceq = [];
end
  2 Comments
Paul AGAMENNONE
Paul AGAMENNONE on 21 Nov 2022
Edited: Paul AGAMENNONE on 21 Nov 2022
This is what the optimization model is supposed to search when it optimizes Rs.
Thus I don't know how to call them in my example

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Accepted Answer

Stephen23
Stephen23 on 21 Nov 2022
Edited: Stephen23 on 21 Nov 2022
The basic problem appears to be your attempt to re-define these parameters again inside every function, thus obliterating the input values. The simple solution is to define them only once and then pass them as input arguments:
The d value seems to be what you are trying to optimize, so you should not specify any values for that, because the d values are provided by FMINCON.
muL = 2000;
sigL = 200;
R1 = 1-9.92*10^-5;
R2 = 1-1.2696*10^-4;
R3 = 1-3.87*10^-6;
Sr1_min = sqrt(((((1.5-1)*muL)/norminv(R1))^2)-(sigL)^2);
Sr1_max = sqrt(((((2.5-1)*muL)/norminv(R1))^2)-(sigL)^2);
Sr2_min = sqrt(((((1.5-1)*muL)/norminv(R2))^2)-(sigL)^2);
Sr2_max = sqrt(((((2.5-1)*muL)/norminv(R2))^2)-(sigL)^2);
Sr3_min = sqrt(((((1.5-1)*muL)/norminv(R3))^2)-(sigL)^2);
Sr3_max = sqrt(((((2.5-1)*muL)/norminv(R3))^2)-(sigL)^2);
lb = [Sr1_min,Sr2_min,Sr3_min];
ub = [Sr1_max,Sr2_max,Sr3_max];
A = [];
B = [];
Aeq = [];
Beq = [];
d0 = (lb+ub)/2;
fun = @(d) parameterfun(d,muL,sigL,R1,R2,R3);
const = @(d) nonlcon(d,muL,sigL,R1,R2,R3);
[d,fval] = fmincon(fun,d0,A,B,Aeq,Beq,lb,ub,const)
Converged to an infeasible point. fmincon stopped because the size of the current step is less than the value of the step size tolerance but constraints are not satisfied to within the value of the constraint tolerance. Consider enabling the interior point method feasibility mode.
d = 1×3
179.9441 186.3380 103.6089
fval = 0.9998
That works without error. Only you can check if it makes sense.
function Rs = parameterfun(d,muL,sigL,R1,R2,R3)
%
mu_Sr1 = muL+norminv(R1)*sqrt((sigL)^2+(d(1))^2);
mu_Sr2 = muL+norminv(R2)*sqrt((sigL)^2+(d(2))^2);
mu_Sr3 = muL+norminv(R3)*sqrt((sigL)^2+(d(3))^2);
%
Y1_mean = muL-mu_Sr1;
Y2_mean = muL-mu_Sr2;
Y3_mean = muL-mu_Sr3;
%
Y1_std = sqrt((d(1))^2+(sigL)^2);
Y2_std = sqrt((d(2))^2+(sigL)^2);
Y3_std = sqrt((d(3))^2+(sigL)^2);
%
Y_mean = [Y1_mean Y2_mean Y3_mean];
Y_std = [(Y1_std^2) (sigL)^2 (sigL)^2; (sigL)^2 (Y2_std)^2 (sigL)^2; (sigL)^2 (sigL)^2 (Y3_std)^2];
%
y = zeros(size(d));
Rs = mvncdf(y, Y_mean, Y_std);
%
end
function [c,ceq] = nonlcon(d,muL,sigL,R1,R2,R3)
%
% You did not define these, so I will presume all have value 1:
L_std = 1;
ns_min = ones(1,3);
ns_max = ones(1,3);
c_min = ones(1,3);
c_max = ones(1,3);
c1_std = 1;
c2_std = 1;
c3_std = 1;
%
c(1) = ns_min(1) - ((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2)))/muL);
c(2) = ns_min(2) - ((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2)))/muL);
c(3) = ns_min(3) - ((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2)))/muL);
c(4) = ((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2)))/muL) - ns_max(1);
c(5) = ((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2)))/muL) - ns_max(2);
c(6) = ((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2)))/muL) - ns_max(3);
c(7) = c_min(1) - (c1_std/((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2)))));
c(8) = c_min(2) - (c2_std/((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2)))));
c(9) = c_min(3) - (c3_std/((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2)))));
c(10) = (c1_std/((muL+norminv(R1)*sqrt((d(1)^2)+(L_std^2))))) - c_max(1);
c(11) = (c2_std/((muL+norminv(R2)*sqrt((d(2)^2)+(L_std^2))))) - c_max(2);
c(12) = (c3_std/((muL+norminv(R3)*sqrt((d(3)^2)+(L_std^2))))) - c_max(3);
%
ceq = [];
%
end
  1 Comment
Paul AGAMENNONE
Paul AGAMENNONE on 21 Nov 2022
Edited: Paul AGAMENNONE on 21 Nov 2022
Thank you Stephen for your answer, I finally understand and the program works perfectly :)

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