How to compute number of bit change among consecutive binary numbers?
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I am having 7 random binary numbers of 3 bit. Now, I need to compute how many number of bits are changed among consecutive numbers.
Example:
A= 110; 101; 011; 111; 100; 001; 010
Expected output:
C=
110 101 011 111 100 001 010
110 - 2 2 1 1 3 1
101 2 - 2 1 1 1 3
011 2 2 - 1 3 2 1
111 1 1 1 - 2 2 2
100 1 1 3 2 - 2 2
001 3 1 1 2 2 - 2
010 1 3 1 2 2 2 -
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Answers (2)
Voss
on 14 Dec 2022
% A = 110; 101; 011; 111; 100; 001; 010
A = dec2bin([6; 5; 3; 7; 4; 1; 2],3)
N = size(A,1);
C = zeros(N);
for ii = 1:N
for jj = 1:N
C(ii,jj) = nnz(A(ii,:) ~= A(jj,:));
end
end
disp(C);
10 Comments
Star Strider
on 15 Dec 2022
b = {'110' '101' '011' '111' '100' '001' '010'};
d = pdist(b, 'hamming');
dmtx = squareform(d*3); % Differences Are Reported As Percentages, So Multiply By The Length Of The Strings To Get Integers
VNRN = cellfun(@(x)sprintf('%s',x),b, 'Unif',0);
Result = array2table(dmtx, 'VariableNames',VNRN, 'RowNames',VNRN) % Create A 'table' To Get The Desired Result
The variable names and row names do not have to be valid MATLAB variable names, however if you want to use them as such, change the ‘VNRN’ function to:
VNRN = cellfun(@(x)sprintf('%_s',x),b, 'Unif',0);
or something similar so that they all begin with a non-numeric character.
.
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