Extracting two columns from 6-D complex double

I have a 6-D complex double and want to only extract the last numbers in the brackets (i.e. 2041 2042 2043......) and the complex number into a 2-D complex array.
e.g. the array should look like
[2041 -2.3832e+02 + 9.7451e+01i]
[2042 2.4313+e02 + 8.3950e+01i]
.......and so on.
And I want to do this calculation to the second column: sqrt( real * real + imag * imag )
and let this calculation to become the new "second row", overwrite the complex numbers.
Any solution to that, please?
Huge thanks in advance!

5 Comments

What is the dimension/ size of the array?
It is a 6-D array with the first five dimension being identical ( : , : , 1 , 1 , 1 )
the size should be 2048.
( : , : , 1 , 1 , 1 )
What is :,:, dimension ?
So are you saying that the size is [1 1 1 1 1 2048]?
If so, there's only one column, so the mention of operating on different "columns" should probably be clarified.
If not, what is the size?
Not sure how I conveyed myself poorly... But the code provided by Matt J below did what I want to do!
Still appreciate you guys' help!

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 Accepted Answer

T=table((1:numel(val))' , abs(val(:)).^2 )

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R2022b

Asked:

on 27 Jan 2023

Commented:

on 27 Jan 2023

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