3d plot from knows XYZ

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May
May on 26 Feb 2023
Commented: Star Strider on 26 Feb 2023
Hello, i have known list of numbers:
x = [0 10 20 30 0 10 20 0 10 20 30];
y = [0 0 0 0 15 15 15 15 30 30 30 30];
t = [20 22 25 23 22 27 30 25 19 20 18 22];
I used: [X,Y] = meshgrid(x,y), but i'm struggeling with understanding what to do with those t values.
thank you

Answers (2)

Star Strider
Star Strider on 26 Feb 2023
Edited: Star Strider on 26 Feb 2023
It will be necessary to interpolate them to create a surface.
There are seeral ways to interpolate them, my favourite being the scatteredInterpolant function.
Try something like this —
x = [0 10 20 30 0 10 20 0 10 20 30];
y = [0 0 0 0 15 15 15 15 30 30 30 30];
t = [20 22 25 23 22 27 30 25 19 20 18 22];
Q = [size(x); size(y); size(t)]
Q = 3×2
1 11 1 12 1 12
y = y(1:numel(x));
t = t(1:numel(x));
xv = linspace(min(x), max(x), numel(x));
yv = linspace(min(y), max(y), numel(y));
[X,Y] = meshgrid(xv,yv);
F = scatteredInterpolant(x(:),y(:),t(:));
Warning: Duplicate data points have been detected and removed - corresponding values have been averaged.
T = F(X,Y);
figure
surfc(X, Y, T)
colormap(turbo)
colorbar
xlabel('X')
ylabel('Y')
zlabel('T')
EDIT — Added axis labels.
.
  2 Comments
Walter Roberson
Walter Roberson on 26 Feb 2023
Note: the duplicate point is because the middle "30" is missing in x, so the 0 of the next x cycle lines up with the 15 of the end of the existing y cycle
0 10 20 0
15 15 15 15
whereas if the 30 had not been missed then it would have been (30,15) for that point instead of a second (0,15)
Star Strider
Star Strider on 26 Feb 2023
@Walter Roberson — That is also likely the origin of the vectors not having equal lengths. I just went with the available data.
I’m also assuming that May wants a surf plot because of the meshgrid call.

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Devargya chakraborty
Devargya chakraborty on 26 Feb 2023
first of all, your vectors should be of the same length.
after that you can use the plot3 command to plot the graph or meshgrid also.
plot3(x,y,t);
meshgrid(x,y,t);

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