关于polyeig函​数为什么polyei​g（A,0,B)与p​olyeig（A,B​）输出的结果不一样

why polyeig（A，0，B) not euqal to polyeig(A,B)

Answer 1

[Abhijeet]

Hi 定毅,

The command polyeig(A, 0, B) computes the eigenvalues of the matrix polynomial A - lambda*B evaluated at lambda=0. This is equivalent to computing the eigenvalues of the matrix A multiplied by the inverse of B.

The command polyeig(A, B) computes the eigenvalues of the matrix polynomial A - lambda*B.

The reason is that evaluating the matrix polynomial at different values of lambda can lead to very different results.

Thanks

[定毅]

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