Vectorising nested for loops

Hi,
I’m trying to vectorise the following code snippet that works using the attached data. Unfortunately, I couldn’t succeed. Any ideas on how to deal with it?
Cheers,
Mel
k=0;
struct_data = struct('idx',[],'count',[],'size',[]);
for i = 1:size(table_data,1)
for j = 1:list(i)
k=k+1;
struct_data(k,1).idx = k;
struct_data(k,1).count = table_data.count(i);
struct_data(k,1).size = table_data.size(i);
end
end

2 Comments

Are you intentionally storing lots of scalar cell arrays containing character vectors, or is the intent to actually just store the character vectors without the superfluous scalar cell arrays? If you only need the text, replace
table_data.size(i);
with
table_data.size{i};
Thank you for your contribution!

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 Accepted Answer

Voss
Voss on 10 Mar 2023
Edited: Voss on 10 Mar 2023
% unzip and load data
unzip data.zip
load data.mat
% run the loop method, for later comparison
k=0;
struct_data = struct('idx',[],'count',[],'size',[]);
for i = 1:size(table_data,1)
for j = 1:list(i)
k=k+1;
struct_data(k,1).idx = k;
struct_data(k,1).count = table_data.count(i);
struct_data(k,1).size = table_data.size{i}; % note this change:
% I made struct_data(k).size a char, instead of
% a scalar cell array containing a char
end
end
struct_data_save = struct_data;
% a "vectorized" method
idx = find(list);
struct_data = table2struct(removevars(table_data(repelem(idx,list(idx)),:),'district'));
C = num2cell(1:numel(struct_data));
[struct_data.idx] = deal(C{:});
% are the results the same?
isequal(struct_data,struct_data_save)
ans = logical
1

2 Comments

If you really want struct_data(k).size to be a 1x1 cell array containing a character vector (as in {'venti'}), as opposed to just a character vector (as in 'venti'), you can do it with a couple of additional lines of code:
% unzip and load data
unzip data.zip
load data.mat
% run the loop method, for later comparison
k=0;
struct_data = struct('idx',[],'count',[],'size',[]);
for i = 1:size(table_data,1)
for j = 1:list(i)
k=k+1;
struct_data(k,1).idx = k;
struct_data(k,1).count = table_data.count(i);
struct_data(k,1).size = table_data.size(i); % scalar cell array this time
end
end
struct_data_save = struct_data;
% a "vectorized" method
idx = find(list);
struct_data = table2struct(removevars(table_data(repelem(idx,list(idx)),:),'district'));
C = num2cell(1:numel(struct_data));
[struct_data.idx] = deal(C{:});
C = num2cell({struct_data.size});
[struct_data.size] = deal(C{:});
% are the results the same?
isequal(struct_data,struct_data_save)
ans = logical
1
That is awesome! Thank you so much for providing solutions for both scenarios🙏

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More Answers (1)

S = load('data.mat')
S = struct with fields:
list: [27×1 double] table_data: [27×3 table]
list = S.list
list = 27×1
0 100 60 0 0 0 0 0 0 0
tdat = S.table_data
tdat = 27×3 table
district count size ________ _____ __________ {[ 1]} 91 {'venti' } {[ 2]} 116 {'venti' } {[ 3]} 112 {'venti' } {[ 4]} 8 {'venti' } {[ 5]} 23 {0×0 char} {[ 6]} 16 {0×0 char} {[ 7]} 7 {0×0 char} {[ 8]} 1 {0×0 char} {[ 9]} 28 {0×0 char} {[10]} 58 {'tall' } {[11]} 43 {'venti' } {[12]} 13 {'trenta'} {[13]} 68 {'tall' } {[14]} 108 {'grande'} {[15]} 102 {'venti' } {[16]} 76 {'venti' }
k=0;
out0 = struct('idx',[],'count',[],'size',[]);
for i = 1:size(tdat,1)
for j = 1:list(i)
k=k+1;
out0(k,1).idx = k;
out0(k,1).count = tdat.count(i);
out0(k,1).size = tdat.size{i};
end % ^ ^ fixed indexing
end
out0
out0 = 160×1 struct array with fields:
idx count size
Without an explicit loop:
out1 = repelem(table2struct(removevars(tdat,'district')),list);
idx = num2cell(1:numel(out1));
[out1.idx] = idx{:}
out1 = 160×1 struct array with fields:
count size idx
isequal(out0,out1)
ans = logical
1

1 Comment

Melanie VT
Melanie VT on 10 Mar 2023
Moved: Stephen23 on 11 Mar 2023
This solution is even almost 1.5 times faster than the one above! I’m truly grateful to you all🙏🏼
This post is also an Accepted Answer with appreciation😊

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on 10 Mar 2023

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on 11 Mar 2023

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