I am getting parse error for this following simple program
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y = 1:3; %parse error at y. It is maybe an invalid mathlab syntax
secondar =[ 3 0 -1] ;
unname = polyfit(y, secondar, 1)
function obiick = solve1(x)
obiick = x^3+x+8 ;
end
Output
solve1(2)
Error: File: solve1.m Line: 6 Column: 1
This statement is not inside any function.
(It follows the END that terminates the definition of the function "solve1".)
4 Comments
Les Beckham
on 15 Mar 2023
Edited: Les Beckham
on 15 Mar 2023
If this is an excerpt from a larger block of code, the error is probably above the first line of code that you posted, since the code you posted does not cause any errors. Oftentimes an incomplete code construct will trigger an error on a line of code that isn't the error but, rather, the first place that the Matlab parser figures out that it can't understand the code and parse it correctly. Please post the complete block of code and, as Matt J suggests, show us the complete error message -- preferably by running your code by clicking the green run button.
Answers (1)
Steven Lord
on 15 Mar 2023
Please show us the full and exact text of the warning and/or error messages you receive (all the text displayed in orange and/or red in the Command Window.) The exact text, not a paraphrased version, may be useful in determining what's going on and how to avoid the warning and/or error.
My suspicion is that you opened a parenthesis, square bracket, or curly brace on a previous line but forgot to close it on that line, something along the lines of:
x = {1+1; % Note no } on this line
y = 2;
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