calculate integral of this function

Hi guys, could you please help me with this simple integral!! Thanks in advance.

p1= 2e-03 ;
p2= 6e-03 ; 
p0=p1+p2;
Pi= p0/2;
theta= deg2rad(60) ; 
H0= tan(theta)*p1 ;
syms H V M0 Fi x
Fi = H0-x*tan(theta);
M=H*Fi+V*x-M0;
dM_dH=diff(M,H);
F1= integral(@(x) (dM_dH).^2/cos(theta),0,Pi)

Answer 1

[Torsten]

F1 = double(int(dM_dH^2/cos(theta),x,0,Pi))

instead of

F1= integral(@(x) (dM_dH).^2/cos(theta),0,Pi)

[Walter Roberson]

I also recommend converting your constants to symbolic

format long g

p1= 2e-03 ;
p2= 6e-03 ; 
p0=p1+p2;
Pi= p0/2;
theta= deg2rad(60) ; 
H0= tan(theta)*p1 ;
syms H V M0 Fi x
Fi = H0-x*tan(theta);
M=H*Fi+V*x-M0;
dM_dH=diff(M,H);
F1s = int(dM_dH^2/cos(theta),x,0,Pi)

F1s = 

F1 = double(F1s)

F1 = 
                   3.2e-08

Q = @(v) sym(v);
p1= Q(2)*sym(10)^(-03) ;
p2= Q(6)*sym(10)^(-03) ; 
p0=p1+p2;
Pi= p0/2;
theta= deg2rad(Q(60)) ; 
H0= tan(theta)*p1 ;
syms H V M0 Fi x
Fi = H0-x*tan(theta);
M=H*Fi+V*x-M0;
dM_dH=diff(M,H);
F1s = int(dM_dH^2/cos(theta),x,0,Pi)

F1s = 

F1 = double(F1s)

F1 = 
                   3.2e-08