Looping for cell arrays
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I have a 3x11 cell array called down_files where each entry in the array is a filename and each of the rows corresponds to a different value for an angle. For example, row 1 corresponds to angle 1, row 2 to angle 2 and so on. The code below worked when the cell array was 1x11, but now that I have added two more rows to it I need to work for 3x11. 
lengths_arr contains values read from each file. So lengths_arr should end up being a 3x11 matrix with each row corresponding to the correct angles again (row 1 for angle 2, row 2 for angle 2.......)
for i = 1:length(down_files)
    file_data = fileread(down_files{i}) 
    f = regexp(file_data, 'length(\d+)?)', 'tokens') % ignore. this is just getting the length values from the files
    if ~isempty(f)
        L = str2double(f{1})
        lengths_arr(end + 1) = L
    end
end
many thanks
1 Comment
  Stephen23
      
      
 on 1 May 2023
				Note that by using a look-around you can avoid one layer of the output's nested cell arrays:
f = regexp(file_data, '(?<=length)\d+)', 'match')
Answers (1)
  chicken vector
      
 on 25 Apr 2023
        Add a second loop for the rows:
for row = 1 : size(down_files,1)
    for col = 1 : size(down_files,2)
        fileread(down_files{row,col});
    end
end
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