Double sum with odd number

I'm not sure how to calculate this sum. Anyone has an idea, please?

n = [1:2:1000];

gamma = 1;

ss = sum(sum((2./(n.*pi)).^6.*(3.*(1 - tanh(n.*pi./(2*gamma))./(n.*pi./(2*gamma)))) - (tanh(n.*pi./(2*gamma))).^2));

[Torsten]

What does the second "sum" symbol sum over ?

[Loïc M.]

I don't know. Here is the complete equation

[Torsten]

From the equation, I don't know either. But you should try to find it out.

Answer 1

[VBBV]

n = [1:2:1000]; 
gamma = 1;
ss = sum(sum((2./(n.*pi)).^6.*(3.*(1 - tanh(n.*pi./(2*gamma))./(n.*pi./(2*gamma))) - tanh(n.*pi./(2*gamma)).^2)))

ss = 0.0272

[VBBV]

The image shows odd values for n in outer summation, but does not tell anything about nature of inner summation. Can you tell more about it ? Does it mean both inner & outer summation are both odd values for n, or ?

[Loïc M.]

I don't know. Here is the complete equation

[VBBV]

Ok, it looks like its double sum over odd integer values for that term as you assumed it i.e.

n = [1:2:1000];