Matrix Data Results Explanation
2 views (last 30 days)
Show older comments
Augusto Gabriel da Costa Pereira
on 16 Sep 2023
Commented: Dyuman Joshi
on 16 Sep 2023
I used the following code, and you can see that in the second row of the fourth column, the result is zero and not NaN; it should be NaN as the result.
%
soma_total = nan(3, 4);
data1 = [nan nan 1 2; 1 2 nan nan; 1 2 nan nan];
data2 = [5 5 nan nan; 2 1 1 nan; nan nan 1 1];
%
result = nansum(cat(3, soma_total, data1, data2), 3);
%
disp(result);
The result was:
[5 5 1 2;
3 3 1 0;
1 2 1 1]
The result should be:
[5 5 1 2;
3 3 1 NaN;
1 2 1 1]
Does anyone have an idea to solve this?
0 Comments
Accepted Answer
Dyuman Joshi
on 16 Sep 2023
Edited: Dyuman Joshi
on 16 Sep 2023
nansum does not do what you are expecting it to do. Also, using nansum() is not recommended as you can see from its documentation page. Use sum instead -
Here's a workaround -
%
soma_total = nan(3, 4);
data1 = [nan nan 1 2; 1 2 nan nan; 1 2 nan nan];
data2 = [5 5 nan nan; 2 1 1 nan; nan nan 1 1];
%Dimension to operate on
dim = 3;
%defining the array
arr = cat(dim, soma_total, data1, data2);
%Finding indices for all elements which are NaN corresponding to the "dim" dimension
idx = all(isnan(arr),dim)
%If you want to use nansum instead, use this command
%result = nansum(arr,dim)
result = sum(arr,dim,'omitnan')
%Converting the respective values back to NaN
result(idx) = NaN
2 Comments
More Answers (0)
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!