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Can anyone explain from the third line till the end of below code..??

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Sombaran Gupta
Sombaran Gupta on 13 Apr 2015
Edited: Thorsten on 14 Apr 2015
a=imread('kmeans.jpg');
imshow(255-rgb2gray(a));
b=reshape(double(255-rgb2gray(a)),[],1);
[idx,c]=kmeans(b,2,'emptyaction','singleton');
Fin_a=reshape(idx,[size(rgb2gray(a))]);
[ind1, ind2]=find(Fin_a(:,:)==2);
[ind3, ind4]=find(Fin_a(:,:)==1);
figure();
imshow(255-rgb2gray(a));
hold on
if(length(ind1)<length(ind3))
scatter(ind2,ind1,'g');
else
scatter(ind4,ind3,'g');a
end

  1 Comment

Thorsten
Thorsten on 14 Apr 2015
Why don't you just run the code line by line and use doc and read what the functions are doing? And then ask again if you can't figure out particular parts/lines.

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Answers (1)

Chris McComb
Chris McComb on 13 Apr 2015
The third line from the end contains only the word 'else'. This is typical syntax for the if control structure. In the example, if length(ind1)<length(ind3), the program executes
scatter(ind2,ind1,'g');
However, if length(ind1)<length(ind3) is not true, the program will try to execute:
scatter(ind4,ind3,'g');a
and exit with an error, because the line ends with an 'a' character.

  2 Comments

John D'Errico
John D'Errico on 14 Apr 2015
I think the question was asking for an explanation starting from line 3 until the end, not the third line from the end.

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