while loop running forever during attempt at Newton Rhapson method

2 views (last 30 days)
This code keeps running seemingly forever, or at least a few minutes. I can't figure out why, could someone please explain what is going wrong? unless i wrote the actual functions of d wrong it should be expected to converge towards something until the while loop condition isn't fullfilled anymore
d=0.007;
dI=1.219;
Rfi=1.76*(10^(-4));
Rf0=Rfi;
hs=356;
ht=hs;
kw=60;
dTm=29.6;
Q=801368;
Aex=64.15;
a=((1/ht)+Rfi)/dI;
b=log(d/dI)/2*kw;
c=d*(a+b)+Rf0+(1/hs);
f=(c^(-1))-Q/(Aex*dTm);
df=-1*(c^(-2))*(a+b)*(dI/(d*2*kw))*(1/dI);
%d1-do ska va mindre än tol
%i slutet av iterationen
%så man kan sätta while
d=0.007;
d0=d;
d1=10;
abs(d1-d0);
while abs(d1-d0)>10^(-8);
d0=d;
d1=d0-f/df;
d=d1;
end
d1

Accepted Answer

VBBV
VBBV on 18 Nov 2023
Edited: VBBV on 18 Nov 2023
d=0.007;
dI=1.219;
Rfi=1.76*(10^(-4));
Rf0=Rfi;
hs=356;
ht=hs;
kw=60;
dTm=29.6;
Q=801368;
Aex=64.15;
a=((1/ht)+Rfi)/dI;
%d1-do ska va mindre än tol
%i slutet av iterationen
%så man kan sätta while
d=0.007;
d0=d;
d1=10;
abs(d1-d0);
while abs(d1-d0)>10^(-8);
b=log(d/dI)/(2*kw);
c=d*(a+b)+Rf0+(1/hs);
f=(c^(-1))-Q/(Aex*dTm);
df=-1*(c^(-2))*(a+b)*(dI/(d*2*kw))*(1/dI);
d0=d;
d1=d0-f/df;
d=d1;
end
d1
d1 = 0.0191
  2 Comments
VBBV
VBBV on 18 Nov 2023
Place the lines of coe inside the while loop which are function of variables d and expression for evaluating d1 inside the while loop
b=log(d/dI)/(2*kw);
c=d*(a+b)+Rf0+(1/hs);
f=(c^(-1))-Q/(Aex*dTm);
df=-1*(c^(-2))*(a+b)*(dI/(d*2*kw))*(1/dI);
Torsten
Torsten on 18 Nov 2023
Are you sure it must read
b=log(d/dI)/(2*kw);
instead of
b=log(d/dI)/2*kw;
as in the original code ?

Sign in to comment.

More Answers (1)

Torsten
Torsten on 18 Nov 2023
Edited: Torsten on 18 Nov 2023
Your function doesn't seem to have a zero.
d=0.007;
dI=1.219;
Rfi=1.76*(10^(-4));
Rf0=Rfi;
hs=356;
ht=hs;
kw=60;
dTm=29.6;
Q=801368;
Aex=64.15;
a=((1/ht)+Rfi)/dI;
b=@(d)log(d/dI)/2*kw;
c=@(d)d.*(a+b(d))+Rf0+(1/hs);
f=@(d)(c(d).^(-1))-Q/(Aex*dTm);
D = 0.1:0.01:10;
plot(D,f(D))
df=@(d)-1*(c(d)^(-2))*(a+b(d))*(dI/(d*2*kw))*(1/dI);
%d1-do ska va mindre än tol
%i slutet av iterationen
%så man kan sätta while
d=0.007;
d0=d;
d1=10;
abs(d1-d0);
while abs(d1-d0)>10^(-8);
d0=d;
%df0 = (f(d0+1e-7)-f(d0))*1e7
d1=d0-f(d0)/df(d0);
% d1 = d0-f(d0)/df0;
d=d1
end
d = 2.6870
d = -2.3299e+07
d = 3.2216e+29 + 6.0366e+28i
d = -3.0746e+96 - 1.9209e+96i
d = -1.4912e+297 +1.6013e+298i
d = Inf + Infi
d = NaN + NaNi
d1
d1 = NaN + NaNi

Categories

Find more on Data Type Identification in Help Center and File Exchange

Products


Release

R2023b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!