I was calculated using the Simpson 1/3 rule numerical method, why my running results doesn't appear in the command window?
1 view (last 30 days)
Show older comments
clear all;
clc;
%input data
a=0;
b=2;
c=1; %centre
f_2=(-1/4*(2)^4)-(1/3*(2)^3)+(5/2*(2)^2)+3*2;
f_0=(-1/4*(0)^4)-(1/3*(0)^3)+(5/2*(0)^2)+3*0;
i=(f_2)-(f_0); %exact
x0=0;
xa=(-x0^3-x0^2+5*x0+3);
x1=0.5;
xb=(-x1^3-x1^2+5*x1+3);
x2=1;
xc=(-x2^3-x2^2+5*x2+3);
ai=((b-a)/6)*(xa+4*(xc)+xb); %main equation
et=(i-ai)/i*100;
i created my own script. the result appear on the workshop, but why it dosen't appear on command window?
please tell me where did i go wrong and how to fix it
0 Comments
Answers (2)
ScottB
on 27 Nov 2023
A semi-colon at the end of a line suppresses display of the result.
0 Comments
Torsten
on 28 Nov 2023
Use
ai=((b-a)/6)*(xa+4*(xb)+xc) %main equation
instead of
ai=((b-a)/6)*(xa+4*(xc)+xb) %main equation
clear all;
clc;
%input data
a=0;
b=2;
c=1; %centre
f_2=(-1/4*(2)^4)-(1/3*(2)^3)+(5/2*(2)^2)+3*2;
f_0=(-1/4*(0)^4)-(1/3*(0)^3)+(5/2*(0)^2)+3*0;
i=(f_2)-(f_0) %exact
x0=0;
xa=(-x0^3-x0^2+5*x0+3);
x1=0.5;
xb=(-x1^3-x1^2+5*x1+3);
x2=1;
xc=(-x2^3-x2^2+5*x2+3);
ai=((b-a)/6)*(xa+4*(xb)+xc) %main equation
et=(i-ai)/i*100;
0 Comments
See Also
Categories
Find more on Downloads in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!