Error: No constructor 'mlreportgen.dom.Number' with matching signature found
11 views (last 30 days)
Show older comments
I have the following code in an app to populate a table in a report template and get the following error: "No constructor 'mlreportgen.dom.Number' with matching signature found" at the line "app.data.all_S(i) = Number(cell2mat(app.UITable.Data(i,1)));"
makeDOMCompilable();
import mlreportgen.report.*
import mlreportgen.dom.*
app.data.all_S = Number();
app.data.all_C = Number();
app.data.all_k = Number();
for i = 1:6
app.data.all_S(i) = Number(cell2mat(app.UITable.Data(i,1))); %Error occurs
app.data.all_S(i).Style = {NumberFormat("%.0f")};
append(D, app.data.all_S(i));
moveToNextHole(D);
app.data.all_C(i) = Number(cell2mat(app.UITable.Data(i,2)));
app.data.all_C(i).Style = {NumberFormat("%.3f")};
append(D, app.data.all_C(i));
moveToNextHole(D);
app.data.all_k(i) = Number(cell2mat(app.UITable.Data(i,3)));
app.data.k(i).Style = {NumberFormat("%.2E")};
append(D, app.data.all_k(i));
moveToNextHole(D);
end
I have the following code in a different app that functions as intended and runs with no errors.
makeDOMCompilable();
import mlreportgen.report.*
import mlreportgen.dom.*
app.data.all_L = Number();
app.data.all_T = Number();
for i = 1:length(app.data.Force)
app.data.all_L(i) = Number(cell2mat(app.UITable.Data(i,2)));
app.data.all_L(i).Style = {NumberFormat("%.2E")};
append(D, app.data.all_L(i));
moveToNextHole(D);
app.data.all_T(i) = Number(cell2mat(app.UITable.Data(i,3)));
app.data.all_T(i).Style = {NumberFormat("%.2E")};
append(D, app.data.all_T(i));
moveToNextHole(D);
end
The first block of code in the new app was copy/paste/edit from the bottom block. I can't figure out why one generates an error and the other does not.
0 Comments
Answers (1)
Varun
on 30 Jan 2024
Hi RGB85,
Looks like you are facing an error “No constructor 'mlreportgen.dom.Number' with matching signature found" and you have copy-pasted and edited the code form bottom block.
It seems like you have defined “app.data.all_k = Number();” and using it as follows:
app.data.all_k(i) = Number(cell2mat(app.UITable.Data(i,3)));
app.data.k(i).Style = {NumberFormat("%.2E")};
But, it you notice you have incorrectly used “app.data.k(i).Style”. You should instead use it as “app.data.all_k(i).Style = {NumberFormat("%.2E")};”.
To learn more about using “uitable”, please refer to the following documentation:
Hope it helps.
See Also
Categories
Find more on MATLAB Report Generator in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!